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2 years ago

KenKen Puzzle 7x7

Mathematics

1 answer:

Ierofanga [76]2 years ago

8 0

$\begin{matrix} 4 & 3 & 6 & 5 & 2 & 1 & 7 \\ 5 & 7 & 4 & 1 & 3 & 2 & 6 \\ 2 & 6 & 1 & 4 & 5 & 7 & 3 \\ 7 & 4 & 3 & 6 & 1 & 5 & 2 \\ 1 & 5 & 7 & 2 & 6 & 3 & 4 \\ 6 & 2 & 5 & 3 & 7 & 4 & 1 \\ 3 & 1 & 2 & 7 & 4 & 6 & 5 \end{matrix}$

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What is the equation of the line that passes through the point (5, 4) and has a slope of 6/5

Sati [7]

Answer:

y=6/5x-2

Step-by-step explanation:

y=mx+C

Y=6/5X+C

4=6+c

c=-2

y=6/5x-2

5 0

3 years ago

What is the solution to this equation? 5(x - 6) + 4 = 7x - 4

dimaraw [331]

5(x - 6) + 4 = 7x - 4

5x - 30 + 4 = 7x - 4

5x - 26 = 7x - 4

5x - 26 + 4 = 7x

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3 years ago

..........................help me pls?

Ludmilka [50]

Answer:

7x-7=y

Step-by-step explanation:

5x+7y=10

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5x/35-10/70=y

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Sana makatulong 

6 0

3 years ago

A population has the following characteristics. (a) A total of 75% of the population survives the first year. Of that 75%, 25% s

Artemon [7]

Answer:

$= \left[\begin{array}{ccc}1344\\84\\28\end{array}\right] \left \begin{array}{ccc}{0 \ \leq age \leq 1 }\\{ 1 \ \leq age \leq 2 }\\{2 \ \leq age \leq 3}\end{array}\right$

i.e after the first year ;

there 1344 members in the first age class

84 members for the second age class; and

28 members for the third age class

Step-by-step explanation:

We can deduce that the age distribution vector x represents the number of population members for each age class; Given that in each class of age there are 112 members present.

The current age distribution vector is as follows:

$x = \left[\begin{array}{ccc}1&1&2\\1&1&2\\1&1&2\end{array}\right] \left[\begin{array}{ccc}{0 \ \leq age \leq 1 }\\{ 0 \ \leq age \leq 2 }\\{0 \ \leq age \leq 3}\end{array}\right]$

Also , the age transition matrix is as follows:

$L = \left[\begin{array}{ccc}3&6&3\\0.75&0&0 \\0&0.25&0\end{array}\right]$

After 1 year ; the age distribution vector will be :

$x_2 =Lx_1 = \left[\begin{array}{ccc}3&6&3\\0.75&0&0 \\0&0.25&0\end{array}\right] \left[\begin{array}{ccc}1&1&2\\1&1&2\\1&1&2\end{array}\right]$

$= \left[\begin{array}{ccc}1344\\84\\28\end{array}\right] \left \begin{array}{ccc}{0 \ \leq age \leq 1 }\\{ 1 \ \leq age \leq 2 }\\{2 \ \leq age \leq 3}\end{array}\right$

6 0

3 years ago

Please answer (-4) + (-5)

sertanlavr [38]

-9

There are the same signs so you'd just add them together and use whatever sign they are..

7 0

3 years ago