ANSWER: $44.10
EXPLANATION: The actual cost for an ice hockey match is $19.60. Now, if the price of the ticket increases by 12.5%, the cost of each ticket will increase by $2.45.
$19.6 x 12.5% = $2.45
So, the final price of a single ticket will be $22.05
$19.6 + $2.45 = $22.05
Hence, the cost of two tickets after the increase will be $44.10
$22.05 x 2 = $44.10
1): Answer =====> Letter Choice, (B), The rate in which you walked home, The slope is the same, as the Rate of Change, In Distance Divided by the Change in Time =====> d = 4 -1/15t(4) / 1/15t
2): The Equation: d = -1/15t + 4
The more the Number of Minutes: Larger the Negative Quantity; ====> -1/15t
The Larger the Negative Quantity in Equation: D value is Smaller:
Therefore your Answer ===> The Distance from home (d), Decreased with Minute Walked (t) ====> So, Letter Choice, (C)
2): Towards your home, The slope is Negative, and the Distance (y - value), Decreases, as the Time (x- Values), Increases. Notice the Slope is Negative, Because, you are getting closer to home.
Hope that helps!!!! : )
Answer:
- 321 adult tickets
- 227 child tickets
Step-by-step explanation:
This sort of problem is easily solved by defining a variable to be the quantity of the higher-value contributor. Here, we can let x represent the number of adult tickets. Then total revenue is ...
6.50x +3.50(548-x) = 2881
3x +1918 = 2881 . . . . . . . . . . . . eliminate parentheses, collect terms
3x = 963 . . . . . . . . . . . . . . . . . . subtract 1918
x = 321 . . . . . . . . . . . . . . . . . . . . divide by 3
548-x = 548 -321 = 227 . . . . . .number of child tickets
321 adult tickets and 227 child tickets were sold.
I hope this helps you
Volume of cone =1/3.pi.r^2.h
Volume of cone =1/3.3,14.6^2.9
Volume of cone =339.12