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elena-14-01-66 [18.8K]
3 years ago
8

N/2 - 2 > 1 solve for N

Mathematics
1 answer:
Drupady [299]3 years ago
3 0

Answer:

n>6

Step-by-step explanation

add two to both sides so far its n/2>3

multiply both sides by 2

n>6

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How do you solve the top two problems ?
IrinaVladis [17]

1. It doesn't matter what the absolute sizes are; the probability is the ratio of the area of the circle to the area of the triangle.


Let's make it the unit circle, radius 1 (so apothem 1 for the triangle) so area \pi.


We can get the area of the triangle a couple of different ways; we'll compare.


Let's call the side of the equilateral triangle s and its height h.


Since the incenter is the centroid for an equilateral triangle, the height is three times the apothem, so h=3. The sides of the right triangle made by the altitude are s/2 and s, so


(s/2)^2 + h^2=s^2


h^2 = \frac 3 4 s^2


s^2 = \frac 4 3 h^2


A =\dfrac{\sqrt{3} s^2}{4} = \dfrac{\sqrt{3} h^2}{3}


We have h=3 so the triangle area is 3 \sqrt{3} and the probability we seek is


Answer: p = \dfrac{\pi}{3 \sqrt{3}}


That's approximately 0.605


2. P(not in circle | in triangle) = 1 - P(in circle | in triangle)


p = 1 -  \dfrac{\pi}{3 \sqrt{3}} = 1 - \pi \sqrt{3}{9}= \dfrac{9 - \pi \sqrt{3}}{9}



Answer: \dfrac{9 - \pi \sqrt{3}}{9}


That's approximately 0.395


Edit: I forgot to do the area another way. I'll add that.


If we connect the tangent points of the incircle, by symmetry we get four congruent equilateral triangles. Any of the three chords makes an isosceles triangle with two radii and included angle 120 degrees. By the law of cosines, the chord length, which is the side of the small equilateral triangle, is


s^2 = 1^2 + 1^2 - 2 (1)(1) \cos 120^\circ = 2 - (2)(-1/2) = 3


so a total triangle area of


4 \times \dfrac{\sqrt{3} s^2}{4}} = 3 \sqrt{3}


which agrees with the previous calculation.




4 0
3 years ago
Please at least help me with one of them cause I have no idea
Fudgin [204]

Answer:

Solving v = \frac{4}{3}\pi r^3 for r gives us: r=\sqrt[3]{\frac{3v}{4\pi}}

Solving a_{ave} = \frac{v_2-v_1}{t_2-t_1} for v2 gives us: v_2 = (t_2-t_1)a_{ave}+v_1

Step-by-step explanation:

Solving an equation for a variable or constant means that we have to isolate the value on one side of the equation or write the whole equation in terms of that variable or constant.

Now,

Solving v = \frac{4}{3}\pi r^3 for r

v = \frac{4}{3}\pi r^3

Multiplying whole equation by 3/4

\frac{3}{4}.v = \frac{3}{4}.\frac{4}{3} \pi r^3

\frac{3}{4}v = \pi r^3

Dividing by Pi on both sides

\frac{3v}{4\pi} = \frac{\pi r^3}{\pi}\\\frac{3v}{4\pi} = r^3

Taking cube root on both sides

\sqrt[3]{r^3} = \sqrt[3]{\frac{3v}{4\pi}}  \\r = \sqrt[3]{\frac{3v}{4\pi}}

Now

Solving a_{ave} = \frac{v_2-v_1}{t_2-t_1} for v2

Multiplying both sides by (t2-t1)

(t_2-t_1)a_{ave} = \frac{v_2-v_1}{t_2-t_1}(t_2-t_1)\\(t_2-t_1)a_{ave} = v_2-v_1

Adding v1 on both sides

(t_2-t_1)a_{ave}+v_1 = v_2-v_1+v_1\\(t_2-t_1)a_{ave}+v_1 = v_2

Hence,

Solving v = \frac{4}{3}\pi r^3 for r gives us: r=\sqrt[3]{\frac{3v}{4\pi}}

Solving a_{ave} = \frac{v_2-v_1}{t_2-t_1} for v2 gives us: v_2 = (t_2-t_1)a_{ave}+v_1

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If the hat costs $975 and the sales tax was 5% how much did rose pay for the hat
Hoochie [10]
$48.75 I take $975 * 0.05=$48.75
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Round 23.0975 to the nearest hundredth
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Answer:

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Step-by-step explanation:

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1 divided by 0.80. Please show work.
lozanna [386]

divide 1 by 0.8=1.25

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