All categories

3 years ago

N/2 - 2 > 1 solve for N

Mathematics

1 answer:

Drupady [299]3 years ago

3 0

Answer:

n>6

Step-by-step explanation

add two to both sides so far its n/2>3

multiply both sides by 2

n>6

You might be interested in

Dilbert and Donna had a combined gross income of $227,300 in 2009. When filing their federal income tax return with the Married

elena55 [62]

Answer:

28% - APEX VERIFIED

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

What is the product of the two matrices? Fill in the missing elements of the resulting matrix.

olganol [36]

The product of the given two matrices comes out to be $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

Here we are given the 2 matrices as follows-

$\left[\begin{array}{ccc}7&-2\\-6&2\end{array}\right] \left[\begin{array}{ccc}1&1\\3&3.5\end{array}\right]$

To find the product of 2 matrices, the number of columns in the first matrix must be equal to the number of rows in the second matrix.

Here since both of the matrices are 2 × 2, their product is possible.

Now, to find the product, we need to multiply each element in the first row by each element of the 1st column of the second matrix and then find their sum. Similarly, we do this for all rows and columns.

Therefore,

$\left[\begin{array}{ccc}(7*1)+(-2*3)&(7*1)+(-2*3.5)\\(-6*1)+(2*3)&(-6*1)+(2*3.5)\end{array}\right]$

= $\left[\begin{array}{ccc}(7)+(-6)&(7)+(-7)\\(-6)+(6)&(-6)+(7)\end{array}\right]$

= $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

Thus, the product of the given two matrices comes out to be $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

Learn more about matrices here-

brainly.com/question/13595915

#SPJ1

3 0

1 year ago

Ignore the stuff underneath I did it in pen and messed up.

Vinil7 [7]

U didn't mess up....
V = pi * r^2 * h....divide both sides by (pi)r^2
V / (pi)r^2 = h

7 0

4 years ago

Which operations are commutative and associative?

Vadim26 [7]

Answer:

Step-by-step explanation:

if there are two numbers a and b.then

1. a+b=b+a ,commutative under addition.

2. ab=ba,commutative under multiplication.

If there are three numbers a,b,c then

1. a+(b+c)=(a+b)+c,associative under addition.

a×(b×c)=(a×b)×c ,associative under multiplication.

6 0

4 years ago

A set of furniture contains one table and four chairs How much does one chair cost, if the table costs 80 dollars and the whole

ankoles [38]

c = chair

200 = 80 + 4c

Subtract 80 from 200

120 = 4c

Divide 120 by 4

30 = c

200 = 80 + 4(30)

One chair costs $30

8 0

3 years ago