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3 years ago

An airplane moves at a constant speed of 120 miles per hour for 3 hours. How many miles does it go?

Mathematics

2 answers:

katrin [286]3 years ago

6 0

Answer:

Someone calculated his or her average speed to 7.46 Miles per hour (mph) This calculation will help you calculate your average speed when you have covered a certain distance over a certain time.

Step-by-step explanation:

The re sults your produce from the speed calculator input will come out in a variety of forms You can also find a report on your speed in terms of kilometres per hour, meters per minute and metres per second. There is also a report on the time it takes you to travel certain distances. This report shows you min:sec per kilometre, seconds per 100 .

irina [24]3 years ago

4 0

Answer:

120 miles per hour

total time 3 hours

120 x 3= 360

the plane travels 360 miles

Step-by-step explanation:

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pychu [463]

Answer:

8/17

Step-by-step explanation:

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2 years ago

Graph this function: y = 2x

77julia77 [94]

Graph is attached below.

Step-by-step explanation:

We have to graph function y = 2x,

From equation, we can see a linear relationship between the values of x and y. This equation shows that the value of y is double than the value of x.

For example,

x = 0

y = 2(0)

y = 0

So, point would be (0,0)

x = 1

y = 2(1)

y = 2

So, point would be (1,2)

x = 3

y = 2(3)

y = 6

So, point would be (3,6)

x = -1

y = 2(-1)

y = -2

So, point would be (-1,-2)

x = -3

y = 2(-3)

y = -6

So, point would be (-3,-6)

By matching these points, a linear graph can easily be drawn. I have also attached the graph pic below.

Keywords: function, graph

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6 0

3 years ago

Use the procedures developed to find the general solution of the differential equation. (Let x be the independent variable.)

makkiz [27]

Solution :

Given :

2y''' + 15y'' + 24y' + 11y= 0

Let x = independent variable

$(a_0D^n + a_1D^{n-1}+a_2D^{n-2} + ....+ a_n) y) = Q(x)$ is a differential equation.

If $Q(x) \neq 0$

It is non homogeneous then,

The general solution = complementary solution + particular integral

If Q(x) = 0

It is called the homogeneous then the general solution = complementary solution.

2y''' + 15y'' + 24y' + 11y= 0

$(2D^3+15D^2+24D+11)y=0$

Auxiliary equation,

$2m^3+15m^2+24m +11 = 0$

-1 | 2 15 24 11

| 0 -2 - 13 -11

2 13 11 0

∴ $2m^2+13m+11=0$

The roots are

$=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$=\frac{-13\pm \sqrt{13^2-4(11)(2)}}{2(2)}$

$=\frac{-13\pm9}{4}$

$=-5.5, -1$

So, $m_1, m_2, m_3 = -1, -1, -5.5$

Then the general solution is :

$= (c_1+c_2 x)e^{-x} + c_3 \ e^{-5.5x}$

8 0

3 years ago

Hi please help me choose the correct answer I will Mark you brainlst

Yuri [45]

Answer:

it's d

Step-by-step explanation:

8 0

4 years ago

Read 2 more answers

Which of the following expressions can be combined?

Rom4ik [11]

Answer: Choice C

Work Shown:

$2\sqrt{12} - 6\sqrt{27}\\\\2\sqrt{4*3} - 6\sqrt{9*3}\\\\2\sqrt{4}*\sqrt{3} - 6\sqrt{9}*\sqrt{3}\\\\2*2*\sqrt{3} - 6*3*\sqrt{3}\\\\4\sqrt{3} - 18\sqrt{3}\\\\(4-18)\sqrt{3}\\\\-14\sqrt{3}\\\\$

In short,

$2\sqrt{12} - 6\sqrt{27}=-14\sqrt{3}$

3 0

2 years ago