Question

Find the 96th term of the arithmetic sequence 1, -12, -25, ...

Answer 1

Answer:

             a₉₆ = - 1234

Step-by-step explanation:

-12 - 1 = -13   and  -25 - (-12) = -13  ⇒  d = -13

$a_n=a_1+d(n-1)\\\\a_1=1\\d=-13\\n=96\\\\a_{96}=1+(-13)(96-1)\\\\a_{96}=1-13\cdot95\\\\a_{96}=1-1235\\\\a_{96}=-1234$