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3 years ago

HELP!! I will give brainliest to best answer! :))

2 answers:

6 0

17) 10•6 = 4w

Multiply:

60 = 4w

Divide:

60/4 = 4w/4

15 = w ———————————

18) 180° - S = 65°

Isolate the variable (subtract 180° on both sides):

-S = -115

You can’t have a negative angle so you divide -1 on both sides:

S = 115 ———————————

Serhud [2]3 years ago

3 0

Answer:

17. w = 15 18. S = 115°

Step-by-step explanation:

17. 10 · 6 = 4w

combine like terms:

=> 60 = 4w

divided by 4 on both sides:

=> w = 15

18. 180° - S = 65°

subtract 180° on both sides:

=> -S = -115° => S = 115°

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Please help me I don't know how to do it

poizon [28]

Findd total collected
add everybody
fri+sat+sun+mon=
21+5 and 5/6+2.75+4 and 5/8
add what you can
21+5+2.75+4+5/6+5/8=
28.75+5/6+5/8
add the fractions by making denom same
5/6+5/8=20/24+15/24=35/24=1 and 9/24=1 and 3/8
28.75+1 and 3/8=29.75+3/8
that is how many barels total
times 205 since that is how many litesr in each bottle
205 times (29.75+3/8)=
205*29.75+205*(3/8)=
6098.75+76.875=
6175.625

29/30 is lost

1//30 remains
9175.625 times 1/30 (aka divided by 30)=205.854166666666666 litesr
205 bottles (and 0.85 partially full bottle)

3 0

3 years ago

1. On her birthday, Shruti bought 2 kg sweets and distributed 1 kg 500 g among her classmates. How much sweets were left with he

uysha [10]

Answer:

500g

Step-by-step explanation:

since she brought 2 kg of sweets, and distributed to her classmates, that means we wil sustract 2 from 1,5 and that will be 0.5 or 500g

I hope I helped you! :)))

7 0

2 years ago

Read 2 more answers

Find the area of the figure.

Viktor [21]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Ionizing radiation is being given increasing attention as a method for preserving horticultural products. A study reports that 1

kolbaska11 [484]

Answer:

Yes, there is enough evidence to support the claim that ionizing radiation is beneficial in terms of marketability.

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that ionizing radiation is beneficial in terms of marketability.

Then, the null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2> 0$

Being π1: the true proportion of treated bulbs that can be comercialized after 240 days, and π2: the true proportion of untreated bulbs that can be comercialized after 240 days.

The significance level is 0.05.

The sample 1, of size n1=180 has a proportion of p1=0.85.

$p_1=X_1/n_1=153/180=0.85$

The sample 2, of size n2=180 has a proportion of p2=0.65.

$p_2=X_2/n_2=117/180=0.65$

The difference between proportions is (p1-p2)=0.2.

$p_d=p_1-p_2=0.85-0.65=0.2$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{153+117}{180+180}=\dfrac{270}{360}=0.75$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.75*0.25}{180}+\dfrac{0.75*0.25}{180}}\\\\\\s_{M_d}=\sqrt{0.001+0.001}=\sqrt{0.002}=0.0456$

Then, we can calculate the z-statistic as:

$z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.2-0}{0.0456}=\dfrac{0.2}{0.0456}=4.382$

This test is a right-tailed test, so the P-value for this test is calculated as (using a z-table):

$P-value=P(t>4.382)=0.000008$

As the P-value (0.000008) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that ionizing radiation is beneficial in terms of marketability.

7 0

3 years ago

The temperature of a substance in an experiment changes by −8.7°F from 10 a.m. to 1 p.m. At 5 p.m., the temperature is 33.5°F. I

NeX [460]

Answer: 33.5

Step-by-step explanation:

3 0

3 years ago