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2 years ago

Please help with this question. Quick! 20 points!

Mathematics

1 answer:

Mnenie [13.5K]2 years ago

7 0

Answer:

Step-by-step explanation:

a is not proportional

b is not proportional

sorry if its wrong this isn't my strong suit

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I need help with the ones that are circled please help it is due tomorrow.

trasher [3.6K]

Poor kid, next time ask your parents or teacher for help or try to find a smart friend that can help you. Go to bed if it is late and make sure you understand your homework before taking it home. Good luck!! :))

6 0

3 years ago

Sabrina read a total of 175 pages in 3 days. On the first day she read 45 pages. On the second and third days, she read the same

Artemon [7]

Answer: Sabrina read 65 pages on the second and third days

Step-by-step explanation:

45 + 2x = 175

45 - 45 + 2x = 175 -45

2x = 130

2x/2 = 130/2

x = 65

CHECK: 45 + 65 +65 = 175

7 0

3 years ago

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When full, a cinema house has n people. When 280 people have taken seat the remaining seats comes to $384 if each tickets cost $

Yuki888 [10]

I don’t understand the question, can you restate it?

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2 years ago

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Find the distance between the two points S(–5, –2) and T(–3, 4).

Oxana [17]

Answer:

(2,6)

Step-by-step explanation:

7 0

2 years ago

Element X decays radioactively with a half life of 12 minutes. If there are 200 grams of Element X, how long, to the nearest ten

Semenov [28]

Answer:

It would take 24 minutes for the element to decay to 50 grams

Step-by-step explanation:

The equation for the amount of the element present, after t minutes, is:

$Q(t) = Q(0)e^{-rt}$

In which Q(X) decays radioactively with a half life of 12 minutes.(0) is the initial amount and r is the rate it decreases.

Half life of 12 minutes

This means that $Q(12) = 0.5Q(0)$

$Q(t) = Q(0)e^{-rt}$

$0.5Q(0) = Q(0)e^{-12r}$

$e^{-12r} = 0.5$

$\ln{e^{-12r}} = \ln{0.5}$

$-12r = \ln{0.5}$

$12r = -\ln{0.5}$

$r = -\frac{\ln{0.5}}{12}$

$r = 0.05776$

If there are 200 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 50 grams?

This is t when Q(t) = 50. Q(0) = 200.

$Q(t) = Q(0)e^{-rt}$

$50 = 200e^{-0.05776t}$

$e^{-0.05776t} = 0.25$

$\ln{e^{-0.05776t}} = \ln{0.25}$

$-0.05776t = \ln{0.25}$

$0.05776t = -\ln{0.25}$

$t = -\frac{\ln{0.25}}{0.05776}$

$t = 24$

It would take 24 minutes for the element to decay to 50 grams

6 0

3 years ago