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Mamont248 [21]
3 years ago
12

Rationalise

0%7D%20" id="TexFormula1" title="{ \frac{1 + \sqrt{3} }{ \sqrt{12} } } " alt="{ \frac{1 + \sqrt{3} }{ \sqrt{12} } } " align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
SOVA2 [1]3 years ago
6 0

Answer:

\frac{2\sqrt{3} + 6}{12}

Step-by-step explanation:

Simplify the denominator of \frac{1 + \sqrt{3} }{\sqrt{12} } completely.

=> \frac{1 + \sqrt{3} }{ \sqrt{(4 \times 3)} } = \frac{1 + \sqrt{3} }{\sqrt{4} \times \sqrt{3}  } = \frac{1 + \sqrt{3} }{2\sqrt{3} }

Now, to rationalise it you need to make the denominator rational.

  • Multiply & divide \frac{1 + \sqrt{3} }{2\sqrt{3} } by 2\sqrt{3}.

=> \frac{1 + \sqrt{3} }{2\sqrt{3} } \times \frac{2\sqrt{3} }{2\sqrt{3} }

=> \frac{(1 + \sqrt{3})\times 2\sqrt{3}  }{2\sqrt{3} \times 2\sqrt{3} }

=> \frac{2\sqrt{3} + 6 }{12}

Arlecino [84]3 years ago
5 0

Answer:

Step-by-step explanation:

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