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Leno4ka [110]
3 years ago
6

Asymptotes of x=3 and y=-2

Mathematics
2 answers:
dimaraw [331]3 years ago
7 0

Answer:

Both of these values don't have asymptotes.

dezoksy [38]3 years ago
6 0

Answer:

Both of these values don't have asymptotes.

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How many acute, obtuse, and right angles are in this figure?
Tanya [424]
Hey!


I hope you don't mind, but before I answer this question I'd like to do a quick review of some general angles and how to tell which is which.

<span><em><u /></em><span><em><u>QUICK REVIEW</u></em>
</span></span>
So, let's first review what an acute angle is. An acute angle is an angle that is smaller than 90<span>°. The word acute basically means having a sharp or pointy end. So this is a helpful way to remember what an acute angle is.

Now, let's review what an obtuse angle is. An obtuse angle is an angle that is more than 90</span>°. If an angle measures over 90<span>° that it is more than likely that it is an obtuse angle.

Last but not least a right angle. A right angle is an angle that has to be exactly 90</span>°. If an angle is 90<span>° than it is most definitely a right 

<span><em><u /></em><span><em><u>END QUICK REVIEW</u></em>
</span></span>
Let's start by finding out the angle in the top left hand corner. The angle is clearly no more that 90</span>° and is not 90° exactly. This angle must be an acute angle. We can also tell that it is an acute angle because the angle is sharp.

Now let's look at the angle on the bottom left hand corner. The angle is clearly no less than 90° and more than 90° exactly. This angle must be an obtuse angle.

Since the angles are basically the same on the other side, we won't be reviewing those. Now we'll count all the angles we have.

Acute Angles - 2

Obtuse Angles - 2

Right Angles - 0

<em>So, this means that in the figure shown above,</em>  there are 2 acute angles, 2 obtuse angles, and no right angles.

Hope this helps!


- Lindsey Frazier ♥
4 0
3 years ago
Determine the domain of the function (fog) (x) where f(x) = 3x-1/x-4 and g(x)=x+1/x
Mrac [35]

Answer:

(-\infty,0)\cup(0, \frac{1}{3})\cup (\frac{1}{3},\infty)

Step-by-step explanation:

The given functions are f(x)=\frac{3x-1}{x-4} and g(x)=\frac{x+1}{x} .

We now composed the two functions to find:

(f\circ g)(x)=f(g(x))

\implies (f\circ g)(x)=f(\frac{x+1}{x})

\implies (f\circ g)(x)=\frac{3(\frac{x+1}{x})+1}{\frac{x+1}{x}-4}

\implies (f\circ g)(x)=\frac{4x+3}{1-3x}

This function is defined if the denominator is not zero.

1-3x\ne0

x\ne\frac{1}{3}

We write this in interval notation as:

(-\infty,\frac{1}{3})\cup (\frac{1}{3},\infty)

We need to be cautious here as x=0 is not in the domain of g(x).

Therefore the domain of (f\circ g)(x) is

(-\infty,0)\cup(0, \frac{1}{3})\cup (\frac{1}{3},\infty)

4 0
3 years ago
PLEASE PLEASE PLEASEEEEE HELP ME PLEASEEE!!!
mafiozo [28]

Answer:

V = 0.523598776

Step-by-step explanation:

3 0
3 years ago
14. Please help. What is the length of PQ⎯⎯⎯⎯⎯⎯⎯⎯?<br> Enter the correct value.
Pepsi [2]

Answer:

The correct value is 5.

5 0
3 years ago
This equation shows how the total number of quizzes Angie has ever taken in high school depends on the number of weeks she has a
zepelin [54]

Answer:

9 weeks

Step-by-step explanation:

Knowing that the "q" is the total number of quizzes, you can set the equation equal to 12, and solve for w.

12 = w + 3     Subtract 3 both sides

9 = w

7 0
3 years ago
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