Functions:graph B,mapping A, Table B
Grape B is a function because it passes the vertical line test ( meaning when I draw a vertical line any where on the graph the line only touched one point),mapping A is a function because each x value has only one y value same with table.
Non function: graph A, mapping B, Table A
Graph A does not pass vertical line test so it is not a function, mapping B and Table A both have an x value that has two y values and that is not a function.
The computation shows that the voter is the first to receive both items is A. the 42nd voter.
<h3>How to compute the value?</h3>
From the information, the candidates running for office are handing out items to voters as every 6th voter gets a button while every 7th voter gets a sticker.
Therefore, it should be noted that the least common multiple of both 6 and 7 is 42. Therefore, the voter is the first to receive both items is the 42nd voter.
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Because the parabola opens down and the vertex is at (0, 5), we conclude that the correct option is:
y = -(1/8)*x² + 5.
<h3>
Which is the equation of the parabola?</h3>
The relevant information is that we have the vertex at (0, 5), and that the parabola opens downwards.
Remember that the parabola only opens downwards if the leading coefficient is negative. Then we can discard the two middle options.
Now, because the parabola has the point (0, 5), we know that when we evaluate the parabola in x = 0, we should get y = 5.
Then the constant term must be 5.
So the correct option is the first one:
y = -(1/8)*x² + 5.
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Answer:
x = 10/-3
Step-by-step explanation:
-3x - 9 = 2 - 1
-3x - 9 = 1
-3x = 1 + 9
-3x = 10
x = 10 / -3
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<u>Answer</u>
B. f(n) = 56(0.5)^n-1
<u>Explanation</u>
f(n) (1) 56
(2) 28
(3) 14
(4) 7
To find the correct relation we have to test all of them.
A. f(n) = 28(0.5)^n
f(1) = 28(0.5)¹
= 28 × 0.5 = 14
<em>f(n) = 28(0.5)^n ⇒ Not correct relation</em>
B. f(n) = 56(0.5)^n-1
f(1) = 56(0.5)¹⁻¹ = 56×1
= 56
F(2) = 56(0.5)²⁻¹ = 56 × 0.5 = 28
F(3) = 56(0.5)³⁻¹ = 56 × 0.25 = 14
<em> f(n) = 56(0.5)^n-1 ⇒ It is the correct relation</em>
C. f(n) = 56(0.5)^n
f(1) = 56(0.5)¹ = 56 × 0.5 = 28
<em>f(n) = 56(0.5)^n ⇒ Not correct relation</em>
D. f(n) = 112(0.5)^n-1
f(1) = 112(0.5)¹⁻¹ = 112 × 1 = 112
<em>f(n) = 112(0.5)^n-1 ⇒ Not correct relation</em>
