Answer:
Given : The high school stadium contains a track that surrounds a soccer field. The soccer field is 100 yards long and 70 yards wide.
The school decided to cover the semicircles with grass to create a space for stretching and other activities.
To Find: area of one of the semicircles at either end of the track
How many square yards of grass will the school need to cover the entire circle?
Solution:
Diameter of semicircle = 70 yards
Radius of semicircle = 70/2 = 35 yards
Area of semicircle at one end = (1/2)πr²
= (1/2)(22/7)35²
= 1,925 sq yards
area of one of the semicircles at either end of the track = 1,925 sq yards
square yards of grass will the school need to cover the entire circle
= 2 x 1,925
= 3850 sq yards
distance around one of the semicircles at either end of the soccer field = πr = (22/7) 35 = 110 yards
distance around the inner lane of the track = 100 + 100 + 110 + 110
= 420 yards
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Answer:
a)
, b)
, c)
, d) 
Step-by-step explanation:
a) The perimeter is the sum of the three sides of the internal square and the remaining sides of the external rectangle, that is:


b) The perimeter is the sum of the two sides of the internal triangle and the remaining sides of the external rectangle, that is:


c) The perimeter is the sum of the two sides of the circular section and the three sides of the lower rectangle, that is:


d) The perimeter is the sum of the external sides of the triangle and rectangle, that is:


4 • 6 = 24
Each student will receive 24 mini loaves of banana bread.
The answer to this question is 8.2 because absolute value is how far away a number is from zero.
length is 15mm
key:
Each 5mm is 10 cm
15/5 =3
There are 3 of 5mm
10 x 3 = 30cm
Answer=30cm
I hope this helped and that it was right.