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uranmaximum [27]
3 years ago
5

<1 and <2 are a linear pair and m<1 = 51°. Find m<2.

Mathematics
1 answer:
12345 [234]3 years ago
7 0

Answer:

its 129

Step-by-step explanation:

just subtract 51 from 180 so like 180-51

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2x ^2 - 9x + 10=\\&#10;2x^2-4x-5x+10=\\&#10;2x(x-2)-5(x-2)=\\&#10;(2x-5)(x-2) \Rightarrow C
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Evaluate the expression \dfrac{x^5}{x^2} x 2 x 5 ​ start fraction, x, start superscript, 5, end superscript, divided by, x, squa
Elza [17]

Answer:

  8

Step-by-step explanation:

Fill in the variable value and do the arithmetic.

  \dfrac{2^5}{2^2}=\dfrac{32}{4}=8

___

Of course, the fraction can be simplified first:

  \dfrac{x^5}{x^2}=x^{5-2}=x^3\\\\2^3=8

7 0
3 years ago
A line that includes the points ( - 1,u) and ( - 2,5) has a slope of - 8. What is the value of u
Andreas93 [3]
U is 6 that is the final answer
5 0
3 years ago
I put in 6.32 for A but it’s still saying it’s wrong and I need the √ , I only need to answer this right to pass my summer schoo
jeka57 [31]

Answer:

A = 2 (on the left). 10 (on the right)

Step-by-step explanation:

Use pythgaros therom

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7 0
3 years ago
Suppose that the weights of airline passenger bags are normally distributed with a mean of 47.88 pounds and a standard deviation
Leto [7]

Answer:

There is a 24.51% probability that he weight of a bag will be greater than the maximum allowable weight of 50 pounds.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem

Suppose that the weights of airline passenger bags are normally distributed with a mean of 47.88 pounds and a standard deviation of 3.09 pounds, so \mu = 47.88, \sigma = 3.09

What is the probability that the weight of a bag will be greater than the maximum allowable weight of 50 pounds?

That is P(X > 50)

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{50 - 47.88}{3.09}

Z = 0.69

Z = 0.69 has a pvalue of 0.7549.

This means that P(X \leq 50) = 0.7549.

We also have that

P(X \leq 50) + P(X > 50) = 1

P(X > 50) = 1 - 0.7549 = 0.2451

There is a 24.51% probability that he weight of a bag will be greater than the maximum allowable weight of 50 pounds.

6 0
3 years ago
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