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Black_prince [1.1K]
3 years ago
5

Can anyone help me with this?

Mathematics
1 answer:
matrenka [14]3 years ago
5 0

Answer:

\sqrt{7}

Step-by-step explanation:

Given

4\sqrt{7} - 10\sqrt{7} + 7\sqrt{7} ( add the coefficients of the terms )

= (4 - 10 + 7) \sqrt{7}

= 1\sqrt{7}

= \sqrt{7}

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Answer:

This is more of a computer kind of thing, but try clicking the next thing at the bottom.

Step-by-step explanation:

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3 years ago
Which values are solutions to the inequality below? check all that apply
Aleonysh [2.5K]

Answer:

Step-by-step explanation:

THE ANSWER IS 9

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4 years ago
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oksano4ka [1.4K]
I am going to do number 2 so when you subtract decimals you have to add two zeros like this 10.00 or 0.25 so now when you subtract you get $9.75
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3 years ago
Help me please thank you
Anuta_ua [19.1K]

S\frac{O}{H}C\frac{A}{H}T\frac{O}{A}   or   Sin\frac{Opposite}{Hypotenuse} Cos\frac{Adjacent}{Hypotenuse} Tan\frac{Opposite}{Adjacent}


The hypotenuse is the longest side of the triangle. The opposite is the side that is across from a point/angle. The adjacent is the side next to a point/angle.


At ∅ (pretend that's theta LOL), 17 is the hypotenuse, 8 is the opposite side, and 15 is the adjacent side.


So:

sin ∅ = Opposite/Hypotenuse

sin ∅ = \frac{8}{17}


cos ∅ = Adjacent/Hypotenuse

cos ∅ = \frac{15}{17}


tan ∅ = Opposite/Adjacent

tan ∅ = \frac{8}{15}

5 0
3 years ago
Using traditional methods, it takes 95 hours to receive a basic flying license. A new license training method using Computer Aid
Snowcat [4.5K]

Answer:

There is not sufficient evidence to support the claim that the technique performs differently than the traditional method.

Step-by-step explanation:

The null hypothesis is:

H_{0} = 95

The alternate hypotesis is:

H_{1} \neq 95

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

A researcher used the technique with 260 students and observed that they had a mean of 94 hours. Assume the standard deviation is known to be 6.

This means, respectively, that n = 260, X = 94, \sigma = 6

The test-statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{94 - 95}{\frac{6}{\sqrt{260}}}

z = -2.69

The pvalue is:

2(P(Z < -2.69))

P(Z < -2.69) is the pvalue of Z when X = -2.69, which looking at the z-table, is 0.0036

2*(0.0036) = 0.0072

0.0072 < 0.01, which means that the null hypothesis is accepted, that is, there is not sufficient evidence to support the claim that the technique performs differently than the traditional method.

7 0
3 years ago
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