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3 years ago

Write and solve an equation to find the value of x. helpppppppppppp meeeeeeeee

Mathematics

1 answer:

Ainat [17]3 years ago

4 0

Answer:

If x = 4

Step-by-step explanation:

Of the triangle:

2x - 4

2(4) - 4

8 - 4

___________________________

2x - 6

2(4) - 6

8 - 6

___________________________

x - 3

4 - 3

Of the rectangle:

3x - 11

3(4) - 11

12 - 11

__________________________

x - 3

4 - 3

Hope this helps

(\) QueTooOfficial (/)

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PLEASE HELP ME!! GEOMETRY! WILL GIVE BRAINLIEST!

Setler [38]

Answer: x=7.5

Step-by-step explanation:

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3 years ago

Ronaldo can kick a soccer ball 35 meters per second which is about 80 mph. He kicked the ball from one end of the field to the o

professor190 [17]

Answer:

$t=3.142sec$

Step-by-step explanation:

From the question we are told that:

Speed of ball $V=35m/s\approx 80 mph$

Length of field $l=110m$

Generally the equation for Time taken $t$ is mathematically given by

$t=m/V$

$t=110/35$

$t=3.142sec$

$t \approx \frac{3.142}{60}$

$t \approx 0.05hrs$

Therefore it will take the ball to get from one end of the field to the other

$t=3.142sec$

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3 years ago

Brianna went on a trip to the art museum and sketched a scale drawing of a rectangular wall mural. She used a scale factor of 0.

zheka24 [161]

Answer:

the wall lenght is 90

Step-by-step explanation:

you know the scale factor is 1/5 so you take the lenght of the drawing and multipy it by 5.

4 0

3 years ago

Read 2 more answers

A 6-pound bag of wheat costs $47.04. What is the price per ounce?

Lena [83]

Answer:

$0.49

Step-by-step explanation:

Using the conversion

1 pound = 16 ounces , then

6 pounds = 6 × 16 = 96 ounces, thus

cost of 1 ounce = $\frac{47.04}{96}$ = $0.49

4 0

3 years ago

In the expansion of (3a + 4b)8, which of the following are possible variable terms? Explain your reasoning. a2b3; a5b3; ab8; b8;

Fiesta28 [93]

We have to find the expansion of $(3a+4b)^{8}$

We will use binomial expansion to expand the given expression, which states that the expression $(a+b)^{n}$ is expanded as :

$(a+b)^{n}=^{n}C_{0}a^{n}+^{n}C_{1}a^{n-1}b+^{n}C_{2}a^{n-2}b^{2}+........^{n}C_{n}b^{n}$

Now expanding $(3a+4b)^{8}$ we get,

$(3a+4b)^{8}=^{8}C_{0}(3a)^{8}+^{8}C_{1}(3a)^{7}(4b)+^{8}C_{2}(3a)^{6}(4b)^{2}+^{8}C_{3}(3a)^{5}(4b)^{3}+^{8}C_{4}(3a)^{4}(4b)^{4}+^{8}C_{5}(3a)^{3}(4b)^{5}+^{8}C_{6}(3a)^{2}(4b)^{6}+^{8}C_{7}(3a)(4b)^{7}+^{8}C_{8}(4b)^{8}$

$(3a+4b)^{8}=^{8}C_{0}(3)^{8}a^{8}+^{8}C_{1}(3)^{7}(4)(a^{7}b)+^{8}C_{2}(3)^{6}(4)^{2}(a^{6}b^{2})+^{8}C_{3}(3)^{5}(4)^{3}(a^{5}b^{3})+^{8}C_{4}(3)^{4}(4)^{4}(a^{4}b^{4})+^{8}C_{5}(3)^{3}(4)^{5}(a^{3}b^{5})+^{8}C_{6}(3)^{2}(4)^{6}(a^{2}b^{6})+^{8}C_{7}(3)(4)^{7}(ab^{7})+^{8}C_{8}(4)^{8}(b^{8})$

So, the variables are $a^{5}b^{3}$ , $b^{8}$ , $a^{4}b^{4}$ , $a^{8} , [tex] ab^{7}$

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3 years ago