Quadratic Formula: (-b +/- sqrt(b^2 - 4ac)) / 2a
2x^2 - 3x = 12
2x^2 - 3x - 12 = 0
a = 2
b = -3
c = -12
(--3 +/- sqrt( (-3)^2 - 4(2)(-12) )) / 2(2)
3 +/- sqrt( 9 + 96 ) / 4
3 +/- sqrt(105) / 4
Answers: 
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Hope this helps!
the answer to this question (-2,3)
This most definitely has to be a rhombus since it is a form of a square with 4 congruent sides where a rectangle only has 4 right angles.
To clarify, a trapezoid only has one pair of parallel sides if you were wondering.
Answer:
The answer to your question is: Yes a parabola can be drawn if we know the focus and the directrix.
Step-by-step explanation:
We can say that it is a vertical parabola that opens downwards.
We conclude that if we graph both the focus and the directrix. Also if we continue the process we can find the vertex (-4, -7) and p = 3.
Ok so assuming the 0 means minus from typing problems
x^2-10x=-8
to completet the square
make sure the term in front of x^2 is 1
that is correct
then take 1/2 of the term in front of the x term and square it
-10/2=-5, (-5)^2=25
add that to both sides
x^2-10x+25=17
answer is the first equation
