In the given question, we come to know that Sammy sold 5 bottles for every 3 water bottles sold by David. In this case we get the ratio as 5:3
Now this ratio indicates that the total number of bottles can be divided into 8 parts for finding out a single part. the total number of water bottles that are sold by Sammy and David together are 160.
Now on dividing this total number of bottles by 8 we get the 20 as one part.
The,
Number of Bottles sold by Sammy = 5 * 20
= 100
Number of bottles sold by David = 3 * 20
= 60
So Sammy sold 100 water bottles and David sold 60 water bottles from the total of 160 water bottles.
I believe it's the first option. Hope this helps.
Answer:
$78, $79.20
Step-by-step explanation:
PART A: $60 times 1.3 = $78
you add 30% to 100% to get 130% since it is a mark up, and then you convert to a decimal by going to the left twice then multiplying by original price.
PART B
Since it is a discount you subtract 15 percent from 100, but then add back 5 percent since there is tax applied to get 90%, convert to decimal and multiply by original price to get $88 x .9 = $79.20
Answer:
Quadrant 4
Step-by-step explanation:
x > 0 means towards right of the origin
y < 0 means below the origin
So Quadrant 4
Answer:
a. For n=25, the mean and standard deviation of the prices of the mobile homes all possible sample mean prices are $63,800 and $1,580, respectively.
b. For n=50, the mean and standard deviation of the prices of the mobile homes all possible sample mean prices are $63,800 and $1,117, respectively.
Step-by-step explanation:
In this case, for each sample size, we have a sampling distribution (a distribution for the population of sample means), with the following parameters:
For n=25 we have:
The spread of the sampling distribution is always smaller than the population spread of the individuals. The spread is smaller as the sample size increase.
This has the implication that is expected to have more precision in the estimation of the population mean when we use bigger samples than smaller ones.
If n=50, we have:
