Find all values of x in the interval [0, 2π] that satisfy the equation. (Enter your answers as a comma-separated list.)

Mathematics

1 answer:

asambeis [7]2 years ago

7 0

Answer:

(15°, 165°)

Step-by-step explanation:

Given the equation 6 sin2(x) = 3, we are to find the value of x that satisfies the equation in the interval [0, 2π]

Given

6 sin2(x) = 3,

Divide both sides by 6

6 sin2(x)/6 = 3/6

sin2(x) = 1/2

2x = sin^-1(0.5)

2x = 30°

x = 30°/2

x = 15°

Since sin is positive in the second quadrant, x2 = 180-15

x = 165°

Hence the values within the interval are 15 and 165.

(15°, 165°)

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