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3 years ago

6

When a snozzberry marmalade machine works at 100% of its capacity, it can make 500 jars of snozzberry marmalade per hour. How ma

ny jars can it make when it is working at only 70% of its capacity

1 answer:

Amiraneli [1.4K]3 years ago

3 0

Answer:

350

Step-by-step explanation:

500*70%=350

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Find the circumference of a circle that has an area of 452.16 square meters. (Use 3.1416 as the value of π.)

laila [671]

$\bf \textit{area of a circle}\\\\
A=\pi r^2\quad 
\begin{cases}
r=radius\\
-----\\
A=452.16
\end{cases}\implies 452.16=\pi r^2\implies \cfrac{452.16}{\pi }=r^2
\\\\\\
\boxed{\sqrt{\cfrac{452.16}{\pi }}=r}\\\\
-------------------------------\\\\
\textit{circumference of a circle}\\\\
C=2\pi r\qquad \qquad \implies C=2\pi \left( \boxed{\sqrt{\cfrac{452.16}{\pi }}} \right)$

so, is just that product, recall to use "<span>3.1416 as the value of π".</span>

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3 years ago

Triangle ABC has verticals A (3,0),B (9,5)and (7,-8) find the length of AC in simplest radical form

AlladinOne [14]

$length = \sqrt{(0+8)^2 + (3-7)^2} = \sqrt{64 + 16} = \sqrt{80} = 4\sqrt{5}$

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4 years ago

Morre Math HARDDDDDDDD

Dafna11 [192]

Answer:

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3 years ago

5000 people went to vote. Candidate Smith claimed 52% of the votes. Candidate Adams claimed 2681 votes. What percentage does can

boyakko [2]

The percentage of votes claimed by Adam is 53.62 %

<em><u>Solution:</u></em>

Given that, 5000 people went to vote

Candidate Smith claimed 52% of the votes. Candidate Adams claimed 2681 votes

To find: Percentage claimed by Adam

From given,

Total number of votes = 5000

Votes claimed by Adam = 2681

<em><u>The formula used is:</u></em>

$Percentage\ claimed\ by\ Adam = \frac{\text{votes claimed by adam}}{\text{Total number of votes}} \times 100$

<em><u>Substituting the values we get,</u></em>

$Percentage\ claimed\ by\ Adam = \frac{2681}{5000} \times 100\\\\Percentage\ claimed\ by\ Adam = 0.5362 \times 100\\\\Percentage\ claimed\ by\ Adam = 53.62$

Thus percentage of votes claimed by Adam is 53.62 %

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3 years ago

How do i prove 2sec^2x-2sec^2xsin^2-sin^2x-cos^2x=1

kramer

$2\sec^2x-2\sec^2x\sin^2x-\sin^2x-\cos^2x=2\sec^2x(1-\sin^2x)-(\sin^2x+\cos^2x)$

Since $\sin^2x+\cos^2x=1$ , you have

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and since $\sec x=\dfrac1{\cos x}$ , you end up with $2-1=1$ .

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