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3 years ago

Please help me with 5 problems of Function Equations.

Mathematics

2 answers:

Vilka [71]3 years ago

8 0

Ok, well the first one I am not sure, but the second one is y=3 because if they give you that x=-2 in a graph then you would look at where the line in x=-2 meets y if you go up the line meets at 3 so y would be actually 3, now the third one I am also not sure and the 4th one is the first one in the right side, because it is a pallalelogram, and the 5th one is the last option, well I got this by plugginh in my info, my graph says taht my y is a -2 so that cuts down one, and my graph says that my rise over run is 2/3 so that cuts down another one, this means that we are left with teh second and last option, but my graph goes up to the right that means my slope is positive so my answer would be the last one

Sorry I couldn't help in some

rodikova [14]3 years ago

5 0

I hope this helps you

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Is (2,4) a solution of 3x - y = 2?

guajiro [1.7K]

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3 years ago

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Find the value of tan theta if sin theta = 12/13 and theta is in quadrant 2

8090 [49]

Answer:

tanΘ = - $\frac{12}{5}$

Step-by-step explanation:

Using the trigonometric identities

• sin²x + cos²x = 1, hence

cosx = ± √(1 - sin²x )

• tanx = $\frac{sinx}{cosx}$

given sinΘ = $\frac{12}{13}$ , then

cosΘ = ± $\sqrt{1-(12/13)^2}$

Since Θ is in the second quadrant where cosΘ < 0, then

cosΘ = - $\sqrt{1-\frac{144}{169} }$

= - $\sqrt{\frac{25}{169} }$ = - $\frac{5}{13}$

tanΘ = $\frac{\frac{12}{13} }{\frac{-5}{13} }$

= $\frac{12}{13}$ × - $\frac{13}{5}$ = - $\frac{12}{5}$

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3 years ago

Describe and correct the error in finding the tenth term of the arithmetic sequence 4, 12, 20, 28.

ycow [4]

Answer: The tenth term is 76

=======================================================

Explanation:

We use this arithmetic sequence formula to get the nth term

$a_n = a_1 + d(n-1)$

Plug in $a_1 = 4, \ d = 8, \ n = 10$ and you should get the following:

$a_n = a_1 + d(n-1)\\\\a_{10} = 4 + 8(10-1)\\\\a_{10} = 4 + 8(9)\\\\a_{10} = \textbf{76}\\\\$

The tenth term is <u>76</u>

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We can verify this by listing out the terms one by one. Start at 4, add on 8 each time, until you generate the 10th term. A table like the one shown below is a good way to keep track of all the terms.

$\begin{array}{c|c}\boldsymbol{n} & \boldsymbol{a_n}\\1 & 4\\2 & 12\\3 & 20\\4 & 28\\5 & 36\\6 & 44\\7 & 52\\8 & 60\\9 & 68\\10 & \textbf{76}\\\end{array}$

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In short, the error is with the "10" in the expression 4+10(8). The student should have used 9 instead. This is because of the n-1 term in $a_n = a_1 + d(n-1)$ which shifts everything one spot to the left.

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2 years ago

What is the solution to the inequality?<br><br> −4(x−6)≤−2x+6

Kipish [7]

-4(x-6) ≤ - 2x+6
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+2x +2x
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Divide both sides by -2
and you get....
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You switch the inequality sign because you're dividing by a negative.
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3 years ago

A parallelogram is a _____. (Choose all that apply)

Mama L [17]

Answer:

Quadrilateral

Step-by-step explanation:

The definition of a parallelogram is a quadrilateral that has two sets of parallel sides.

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2 years ago

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