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2 years ago

PLEASE HELP ASAP 30 POINTS

Mathematics

1 answer:

Yuki888 [10]2 years ago

8 0

Answer:

I don't know how to do please let me I will try solve the question

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the lenghty of a rectangal is 8 feet more than its width. the pirimete of the rectangle is 72 feet. Find the width

morpeh [17]

Width of the rectangle is 14 ft

Step-by-step explanation:

Step 1: Let the width of the rectangle be x. Then length = 8 + x. Perimeter = 72 ft.

Perimeter = 2(length + width)

72 = 2 (8 + x + x)

72 = 16 + 4x

4x = 56

x = 56/4 = 14

∴ Width of the rectangle is 14 ft

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3 years ago

What is the range of -2,-1,0,1,3

masya89 [10]

Answer: 5

Step-by-step explanation: 3 - (-2) = 5

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2 years ago

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2 years ago

Work out the volume of the sphere

Marrrta [24]

Answer:

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Step-by-step explanation:

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4 0

2 years ago

a card is chosen from a standard deck of cards. what is the probability that the card is a queen, given that the card is a club?

Dmitrij [34]

Answer:

Probability that card is queen given that card is club is $\frac{4}{13}$

Step-by-step explanation:

Given : A card is chosen from a standard deck of cards.

To find : What is the probability that the card is a queen, given that the card is a club?

Solution : It is the conditional probability

$P(A|B)=\frac{P(A\cap B)}{P(B)}$

Let A is probability that card is queen.

Let B is the probability that card is a club.

Probability that card is queen given card is club $P(A\cap B)=\frac{4}{52}=\frac{1}{13}$

Probability that card is club from deck of 52 cards $P(B)=\frac{13}{52}=\frac{1}{4}$

To find probability that card is queen given that card is club $P(A|B)$

$P(A|B)=\frac{P(A\cap B)}{P(B)}$

$P(A|B)=\frac{\frac{1}{13}}{\frac{1}{4}}$

$P(A|B)=\frac{1\times4}{13\times 1}=\frac{4}{13}$

Therefore, Option A is correct.

Probability that card is queen given that card is club is $\frac{4}{13}$

7 0

3 years ago

Read 2 more answers