Question

Sergei wants to prove that Triangle ABC is similar to Triangle FGH

Answer 1

Answer:

Option (A) and (E) are correct.

We can prove  ΔABC and ΔFGH  are similar by AA criterion or by showing that the  ratio of corresponding sides are equal.

Step-by-step explanation:

Given : two triangles, ΔABC and ΔFGH and we need to prove both are similar to each other.

We have to choose the correct options from the given choices.

 Two triangles are said to be similar if their the corresponding sides are in proportion and the corresponding angles are congruent to each other.

 that is $\frac{AB}{FG}=\frac{AC}{FH}=\frac{BC}{GH}$

also measure ∠A and  ∠F  to show they are congruent as ∠H= ∠C = 90°

This can be observed by looking at the image . So when both triangle are congruent we an show by AA similarity criterion that  ΔABC and ΔFGH  are similar.

Thus, option (A) and (E) are correct.

We can prove  ΔABC and ΔFGH  are similar by AA criterion or by showing that the  ratio of corresponding sides are equal.

Answer 2

Answer:

A and E

Step-by-step explanation: