Sergei wants to prove that Triangle ABC is similar to Triangle FGH
2 answers:
Answer:
Option (A) and (E) are correct.
We can prove ΔABC and ΔFGH are similar by AA criterion or by showing that the ratio of corresponding sides are equal.
Step-by-step explanation:
Given : two triangles, ΔABC and ΔFGH and we need to prove both are similar to each other.
We have to choose the correct options from the given choices.
Two triangles are said to be similar if their the corresponding sides are in proportion and the corresponding angles are congruent to each other.
that is
also measure ∠A and ∠F to show they are congruent as ∠H= ∠C = 90°
This can be observed by looking at the image . So when both triangle are congruent we an show by AA similarity criterion that ΔABC and ΔFGH are similar.
Thus, option (A) and (E) are correct.
We can prove ΔABC and ΔFGH are similar by AA criterion or by showing that the ratio of corresponding sides are equal.
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Because y varies inversely as x, therefore
where k = constant.
When x = 6, y = 2.5. Ther efore
Cross multiply.
k = 6 x 2.5 = 15
The equation is
When x = 4, obtain
Answer: a. 3.75
where k = constant.
When x = 6, y = 2.5. Ther efore
Cross multiply.
k = 6 x 2.5 = 15
The equation is
When x = 4, obtain
Answer: a. 3.75
Answer:
The correct answer is 2.912 cm.
Step-by-step explanation:
A company is designing a new cylindrical water bottle.
Volume of a cylinder is given by π × × h, where h is the height of the cylinder and r is the radius of the cylinder.
The volume of each bottle will be 211 .
The height (h) of the water bottle be 7.9 cm.
Let the radius of the bottle be r cm.
∴ π × × h = 211 ; (π = 3.15)
⇒ × 24.885 = 211
⇒ r = 2.912
The radius of the water bottle is 2.912 cm.