A bee colony produced 5.9 pounds of honey, but bears ate 1.5 pounds of it. How much honey remains?

4x^3(5x) = what,<br> will mark brainliest

Alisiya [41]

The answer to that is 20x^4

7 0

2 years ago

A race car can complete 8 laps in 1/3 hour. At this rate, how many hours will it take the race car to complete 1 lap? 1/240 1/24

Marrrta [24]

Answer:

Step-by-step explanation:

The race car is doing 8 laps in 1/3 hour, in one hour the car is doing:

8laps * (1/3) hour) = 8*3 laps / 1hour = 24 laps/hour.

Now, to complete one lap, the car will it take:

1 lap * (1 hour / 24 laps) = 1/24 hours the race car requires to complete 1 lap. Right answer is:

8 0

3 years ago

i am a multiple of 7, i am also a mutiple of 3 my units digit is half my tens digit. Thanks!

givi [52]

Answer:

21 or 42......both work

5 0

2 years ago

Choose the correct problem formulation: Hotels, like airlines, often overbook, counting on the fact that some people with reserv

Marina CMI [18]

Answer:

$P(8 < x \leq 12)=P(X=9)+P(X=10)+P(X=11)+P(X=12)$

$P(X=9)=(15C9)(0.8)^{9} (1-0.8)^{15-9}=0.0429$

$P(X=10)=(15C10)(0.8)^{10} (1-0.8)^{15-10}=0.1032$

$P(X=11)=(15C11)(0.8)^{11} (1-0.8)^{15-11}=0.1878$

$P(X=12)=(15C12)(0.8)^{12} (1-0.8)^{15-12}=0.2501$

$P(8 < x \leq 12)=0.0429+0.1032+0.1878 +0.2501=0.5839$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=15, p=1-0.2=0.8)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want to find this probability:

$P(8 < x \leq 12)=P(X=9)+P(X=10)+P(X=11)+P(X=12)$

$P(X=9)=(15C9)(0.8)^{9} (1-0.8)^{15-9}=0.0429$

$P(X=10)=(15C10)(0.8)^{10} (1-0.8)^{15-10}=0.1032$

$P(X=11)=(15C11)(0.8)^{11} (1-0.8)^{15-11}=0.1878$

$P(X=12)=(15C12)(0.8)^{12} (1-0.8)^{15-12}=0.2501$

$P(8 < x \leq 12)=0.0429+0.1032+0.1878 +0.2501=0.5839$

7 0

3 years ago

Which comparison of the two equations is accurate?

sveticcg [70]

9514 1404 393

Answer:

(c) Both equations have the same potential solutions, but equation A might have extraneous solutions.

Step-by-step explanation:

The general approach to solving an equation like either of these is to raise both sides of the equation to a power that will remove the radical. In both cases, the result is a quadratic with roots of x=-4 and x=2.

Of these two potential solutions, x = -4 is an extraneous solution for equation A. Both values of x are solutions for equation B. An appropriate description is ...

Both equations have the same potential solutions, but equation A might have extraneous solutions.

_____

<em>Additional comment</em>

The attached graph shows the equations cast into the form f(x) = 0, so x-intercepts are the solutions to the equation. The radical versions of the equations have only x-intercepts that are actual solutions. The version with the radicals removed is a parabola with two solutions (orange). Only one of those matches the solution to equation A (red). Both match the solutions of equation B (purple).

8 0

3 years ago