Pythagoras' Theorem only works with right angle triangles.
A makes a right angles triangle because:
√3² + 4² = 5
However B doesn't because:
√7² + 8² = 10.631 (which is not 9)
Nor does C because:
√3² + 9² = √90 (which is not √95)
So the answer is A
Answer:
When x = 0, then y = -2
When y = 0, then x = 4
Step-by-step explanation:
We are given with the following equation;
x - 2y = 4
Now, we have to find the respective values of x and y for each value of x = 0 and y = 0.
Firstly, putting the value of x = 0;
x - 2y = 4
0 - 2y = 4
-2y = 4
y = 
= -2
This means that when x = 0, then y = -2.
Similarly, putting the value of y = 0;
x - 2y = 4
x - 0 = 4
x = 4
This means that when y = 0, then x = 4.
Answer:
the question is incomplete, below is the complete question
"ress the following complex numbers in rectangular form. Show how you get the answer and use a calculator to verify your answer. E.g. 2 pts for 2∠30°=2(cos30°+jsin30°)=1.73+j, 1 pt for 2∠30°=1.73+j. Same grading criteria as 1.4. (a) Z1=5eⁱ³⁰ (b) z2=−3 ∠(−45°) (c) z3=2∠(−90°)
answer
a.Z1=4.33+j2.5
b. Z2=-2.12+j2.12
c.Z3=-2j
Step-by-step explanation
note that
Z=reⁱⁿ=r(cosπ+jsinπ)
hence from Z1=5eⁱ³⁰ wen have
Z1=5(cos30+jsin30)
Z1=5(0.8660+j0.5)
Z1=4.33+j2.5
b.also from z=r∠(π)=r(cosπ+jsinπ)
Hence,
z2=−3 ∠(−45°)=-3(cos(-45)+jsin(-45))
Z2=-3(0.7071-j0.7071)
Z2=-2.12+j2.12
c. z3=2∠(−90°)=2(cos(-90)+jsin(-90))
Z3=2(0-j)
Z3=-2j
Answer:
Apartment 1 is his best option
3.6 because
a^2 =13
the square root of 13 is 3.6 rounded to the nearest tenth
