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Oksi-84 [34.3K]

3 years ago

7

How many ways can you arrange 28

1 answer:

MaRussiya [10]3 years ago

3 0

Answer:

In 6 ways 28 can be arranged

Step-by-step explanation:

1 × 28 = 28

2 × 14 = 28

4 × 7 = 28

7 × 4 = 28

14 × 2 = 28

28 × 1 = 28

Thus, In 6 ways 28 can be arranged

<em><u>-TheUnknownScientist</u></em>

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Consider the function below. f(x)= x^3 + 2x^2 - x - 2 plot the x and y intercepts of the function

dimulka [17.4K]

In the Figure below is shown the graph of this function. We have the following function:

$f(x)=x^3+2x^2-x-2$

The $y-intercept$ occurs when $x=0$ , so:

$f(0)=(0)^3+2(0)^2-(0)-2=-2$

Therefore, the $y-intercept$ is the given by the point:

$\boxed{(0,-2)}$

From the figure we have three $x-intercepts$ :

$\boxed{P_{1}(-2,0)} \\ \boxed{P_{2}(-1,0)} \\ \boxed{P_{3}(1,0)}$

So, the $x-intercepts$ occur when $y=0$ . Thus, proving this:

$f(x)=x^3+2x^2-x-2 \\ \\ For \ P_{1}:\\ If \ x=-2, \ y=(-2)^3+2(-2)^2-(-2)-2=0 \\ \\ For \ P_{2}:\\ If \ x=-1, \ y=(-1)^3+2(-1)^2-(-1)-2=0 \\ \\ For \ P_{3}:\\ If \ x=1, \ y=(1)^3+2(1)^2-(1)-2=0$

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3 years ago

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zhuklara [117]

This answer is going to be X=-5 because you are solving for X in the parentheses.

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3 years ago

Please help me 10 points will give crown

Lubov Fominskaja [6]

A,d,b, and then c ,basically least to greatest

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valina [46]

Answer:

1225miles

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8 0

3 years ago

Find the standard deviation of the following data. Round your answer to one decimal place. x 0 1 2 3 4 5 P(X

lbvjy [14]

Answer:

<em></em> $\sigma = 1.8$ <em></em>

<em></em>

Step-by-step explanation:

Given

$\begin{array}{ccccccc}x & {0} & {1} & {2} & {3} & {4}& {5} \ \\ P(x) & {0.2} & {0.1} & {0.1} & {0.2} & {0.2}& {0.2} \ \end{array}$

Required

The standard deviation

First, calculate the expected value E(x)

$E(x) = \sum x * P(x)$

So, we have:

$E(x) = 0 * 0.2 + 1 * 0.1 + 2 * 0.1 + 3 * 0.2 + 4 * 0.2 + 5 * 0.2$

$E(x) = 2.7$

Next, calculate E(x^2)

$E(x^2) = \sum x^2 * P(x)$

So, we have:

$E(x^2) = 0^2 * 0.2 + 1^2 * 0.1 + 2^2 * 0.1 + 3^2 * 0.2 + 4^2 * 0.2 + 5^2 * 0.2$

$E(x^2) = 10.5$

The standard deviation is:

$\sigma = \sqrt{E(x^2) - (E(x))^2}$

$\sigma = \sqrt{10.5 - 2.7^2}$

$\sigma = \sqrt{10.5 - 7.29}$

$\sigma = \sqrt{3.21}$

<em></em> $\sigma = 1.8$ <em> --- approximated</em>

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3 years ago