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maksim [4K]
2 years ago
9

A father's age now is three times the age that his son was four years ago. In 12 years, the father will be twice as old as his s

on. Find their ages.
Mathematics
1 answer:
irina1246 [14]2 years ago
8 0

Answer:

Now, the father is 60, and the son is 24.

Step-by-step explanation:

Now:

Father's age = f

Son's age = s

4 years ago:

Father's age = f - 4

Son's age = s - 4

In 12 years:

Father's age = f + 12

Son's age = s + 12

Now:

f = 3(s - 4)

In 12 years:

f + 12 = 2(s + 12)

We have 2 equations that we can solve in a system of equations.

f = 3(s - 4)

f + 12 = 2(s + 12)

f = 3s - 12

f + 12 = 2s + 24

f = 3s - 12

f = 2s + 12

Since above both equations are in terms of f, set the right sides equal and solve for s.

3s - 12 = 2s + 12

s = 24

f = 3(s - 4)

f = 3(24 - 4)

f = 3(20)

f = 60

Now, the father is 60, and the son is 24.

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