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Semmy [17]
4 years ago
5

Please help I’ll give you guys brainiest! Thank youuuuuuu :))!!!!!!!!!! !!!!!!!!!

Mathematics
1 answer:
user100 [1]4 years ago
3 0

Answer:

yes

yes

no

no

no

Step-by-step explanation:

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Directed line segment overline FG has endpoints F(4, 9) and G(- 8, - 9) .On the coordinate plane below , plot a point that parti
Thepotemich [5.8K]

Answer:

The coordinates of the point that makes the division in the given ratio is (0,3)

Step-by-step explanation:

Here, we want to find the point on the line segment that divides the line segment in the ratio 1:2

We simply use the internal division formula

That would be;

(x,y) = (nx1 + mx2)/(m + n) , (ny1 + my2)/(m + n)

m = 1 and n = 2

(x1,y1) = (4,9)

(x2,y2) = (-8,-9)

Substituting these values into the formula, we have;

2(4) + 1(-8)/(1 + 2) , 2(9) + 1(-9)/(2 + 1)

= (8-8)/3 , (18-9)/3

= (0,3)

5 0
3 years ago
HELP!!! I WILL GIVE BRAINY!!!
RideAnS [48]

Answer:

C

Step-by-step explanation:

In the attached file

6 0
3 years ago
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There are 180 girls in a mixed school. if the ratio of girls to boys is 4 : 3,
Gennadij [26K]

Answer:

that is the solution to the question

6 0
4 years ago
Helpp me please lol :)
netineya [11]

Answer:

c

Step-by-step explanation:

4 0
3 years ago
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How would I do the steps to solve this?
allsm [11]

Answer:

The maximum revenue is 16000 dollars (at p = 40)

Step-by-step explanation:

One way to find the maximum value is derivatives. The first derivative is used to find where the slope of function will be zero.

Given function is:

R(p) = -10p^2+800p

Taking derivative wrt p

\frac{d}{dp} (R(p) = \frac{d}{dp} (-10p^2+800p)\\R'(p) = -10 \frac{d}{dp} (p^2) +800 \ frac{d}{dp}(p)\\R'(p) = -10 (2p) +800(1)\\R'(p) = -20p+800\\

Now putting R'(p) = 0

-20p+800 = 0\\-20p = -800\\\frac{-20p}{-20} = \frac{-800}{-20}\\p = 40

As p is is positive and the second derivative is -20, the function will have maximum value at p = 40

Putting p=40 in function

R(40) = -10(40)^2 +800(40)\\= -10(1600) + 32000\\=-16000+32000\\=16000

The maximum revenue is 16000 dollars (at p = 40)

3 0
3 years ago
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