We try to factor by maybe grouping
experiment
(x²y³-11x²y)+(6y²-66)
factor
x²y(y²-11)+6(y²-11)
undistribute (y²-11) from each
(x²y+6)(y²-11)
we can force a factor out of the 2nd group in the form of a difference of 2 perfect squares
(x²y+6)(y-√11)(y+√11)
either of those 3 are factors
The area of the figure is 9
Let
a1=1/40
a2=4/40
a3=9/40
a4=16/40
a5=25/40
a6=?
we know that
a2-a1=4/40-1/40----> 3/40
a3-a2=9/40-4/40-----> 5/40
a4-a3=16/40-9/40----> 7/40
a5-a4=25/40-16/40---> 9/40
the difference is
3/40,5/40,7/40.9/40,....
3/40+[2/40]---> 5/40
5/40+[2/40]---> 7/40
7/40+[2/40]---> 9/40
the next will be
9/40+[2/40]-----> 11/40
so
the next term is 25/40+[11/40]------> 36/40
the answer is
36/40
Answer:
- Both expressions should be evaluated with two different values. If for each substituted value, the final values of the expressions are the same, then the two expressions must be equivalent.
Step-by-step explanation:
<u>Given expressions</u>
- 4x - x + 5 = 3x + 5
- 8 - 3x - 3 = -3x + 5
Compared, we see the expressions are different as 3x and -3x have different coefficient
<u>Answer options</u>
Both expressions should be evaluated with one value. If the final values of the expressions are both positive, then the two expressions must be equivalent.
- Incorrect. Positive outcome doesn't mean equivalent
----------------------------------------
Both expressions should be evaluated with one value. If the final values of the expressions are the same, then the two expressions must be equivalent.
- Incorrect. There are 2 values- variable and constant
----------------------------------------
Both expressions should be evaluated with two different values. If for each substituted value, the final values of the expressions are positive, then the two expressions must be equivalent.
- Incorrect. Positive outcome doesn't mean equivalent.
----------------------------------------
Both expressions should be evaluated with two different values. If for each substituted value, the final values of the expressions are the same, then the two expressions must be equivalent.
