Question

Find ad please help aghhhh due today

Answer 1

Question :-

Find AD.

$\sf a. \: 2\sqrt{3} \: m$

$\sf b. \: 3 \sqrt{3} \: m$

$\sf c. \: 6 \: m$

$\sf d. \: 6 \sqrt{3}$

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Solution :-

Given Information :-

• ∠DCB = 30°
• ∠BDC = 90°
• ∠ABC = 90°
• BC = 12 m

To Find :-

• The Length of AD

Calculation :-

Here, Sin θ is 30°

Sin = $\bf \frac{perpendicular}{hypotenuse}$

Here, θ is 30°

Substituting the values, We get,

∴ Sin ( 30 ) = $\sf \frac{AD}{BC}$

Substituting the value of BC as 12, We get,

⇒ Sin ( 30 ) = $\sf \frac{AD}{12}$

Transposing 12 to Left Hand Side, We get,

⇒ Sin ( 30 ) × 12 = AD

Calculating further, We get,

⇒ AD = 6 m

∴ AD = 6 m

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Final Answer :-

The Length of AD is 6 m

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Answer 2

Answer:

AD = 6m

Step-by-step explanation:

Sin(30) = AD / 12

Sin(30) * 12 = AD

6 = AD

Hope this helps!