Answer:
7^8 =5764801 * 7^3 =343 * 7^4 =2401 ÷ 7^9 = 40353607 * 7^5 =16807
5764801 *343 *2401 ÷ 40353607 *16807
=4747561509943 ÷ 678223072849 = 7
Is this chemistry, their are many apps online that do you it automatically for u
Answer:
Step-by-step explanation:
The system of equations is given as
y=x^2-5x+7 - - - - - - - - - - 1
y=2x+1 - - - - - - - - - - - - - - 2
We would equate equation 1 to equation 2, it becomes
x^2-5x+7 = 2x+1
x^2-5x+7- 2x - 1 = 0
x^2-5x+7- 2x - 1 = 0
x^2 - 5x - 2x + 7 - 1 = 0
x^2 - 7x + 6 = 0
We would use the factorization method of solving quadratic equations.
x^2 - 6x - x + 6 = 0
x(x - 6) - 1(x - 6)
(x - 6)(x - 1) = 0
x - 6 = 0 or x - 1 = 0
x = 6 or x = 1
Substituting both values of x into equation 2, it becomes
For x = 6,
y=2×6 + 1 = 12 + 1 = 13
y = 13
For x = 1,
y=2 × 1 +1 = 2 + 1 = 3
y = 3
Answer:
as p decreases, sigma decreases.
Step-by-step explanation:
Given that 35%are hispanic. For a sample of 17 members
n = 17
p = 0.35
and the number of Hispanics on the committee would have the binomial distribution
a) Mean of X = E(x) = 
b) Std dev X = 
c) Here n =17 and p =0.1
d) When p = 0.01
Thus we find that as p decreases, sigma decreases.
- The IQR for the males' data is 25.
- The difference between the median of the males' data and the female's data is 14.
- The distribution of the males' data is skewed to the right and the median would be a better measure of the center. The distribution of the female's data is normal and the mean would be a better measure of the center.
- A reason for the outlier is that the number of dogs needing care increased.
<h3>What is the interquartile range?</h3>
The interquartile range for the males data is the difference between the third quartile and the first quartile.
IQR = third quartile - first quartile
25 - 0 = 25
Median = 20 - 6 = 14
An outlier is a number that is way smaller or way larger than that of other numbers in a data set.
To learn more about outliers, please check: brainly.com/question/27197311
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