Answer:
The numerical length of JL is 6 units
Step-by-step explanation:
Here, we want to determine the numerical length of JL
Mathematically;
JL = JK + KL
2x + 8 = 5x + 7 + 4
2x + 8 = 5x + 11
5x -2x = 8-11
3x = -3
x = -1
But JL = 2x + 8
JL = 2(-1) + 8 = -2 + 8 = 6
Answer:
about 20 ft
Step-by-step explanation:
1.
the absolute value of (-3) is 3
4 - 3
1
For this one, instead of breaking it down into 3 shapes we can simply subtract the missing square area from the total enclosing area...
15*8-4*4
120-16
104 cm^2
Answer: g(h(3)) = 59
Step-by-step explanation:
Well if its x^3 I assume it is because you wrote other coefficients before the variable.
2(3) - 2 = 6-2 = 4
So 4 is the x input for h(x)
4^3 -5 = 64-5 = 59
