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3 years ago

9

if y is inversely proportional to 2x + 1 and the difference in the values of y when x= 0.5 and x= 2 is 0.9, find the value of y

when x = -0.25

1 answer:

Anna35 [415]3 years ago

5 0

Answer:

6

Step-by-step explanation:

answer is in photo above

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For a parallelogram with a long side that is 4 times the length of its short side find the area if the height from the long side

Zielflug [23.3K]

9514 1404 393

Answer:

c. 1150 square units

Step-by-step explanation:

The sum of the two side lengths is half the perimeter, so is 125/2 = 62.5 units. The long side is 4/5 of that, so is 50 units.

The area is the product of the long side and the height to the long side:

A = bh

A = (50 units)(23 units) = 1150 units²

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<em>Additional comment</em>

This geometry is impossible, because the height from the long side cannot be more than the length of the short side. Here, the short side is 12.5 units, so it is not possible for the height to be 23 units.

If the height is measured from the short side, then the area is 287.5 square units.

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larry has 3 packer sin each 15 and total are 45 u wish put in 10 bags then divide 45 by 10 anser is 5

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Which sum equalas 11 over 12

lianna [129]

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Solve the equation. StartFraction dx Over dt EndFraction equals StartFraction 1 Over x e Superscript t plus 7 x EndFraction An i

MAVERICK [17]

Answer:

$\frac{1}{49}(7x-1)e^{7x}+e^{-t}=C$

Step-by-step explanation:

We are given that

$\frac{dx}{dt}=\frac{1}{xe^{t+7x}}$

We have to find the implicit function

Using separation variable method

$\frac{dx}{dt}=\frac{1}{xe^t\cdot e^{7x}}$

By using property $x^a\cdot x^y=x^{a+y}$

$xe^{7x}dx=e^{-t}dt$

By using property $\frac{1}{x^a}=x^{-a}$

Taking integration on both sides

$\int xe^{7x}dx=\int e^{-t}dt$

Parts integration method

$\int u\cdot v dx=u\int vdx-\int (\frac{du}{dx}\int vdx)dx$

By parts integration method

$x\int e^{7x}dx-\int (\frac{dx}{dx}\int e^{7x}dx)dx=-e^{-t}+C$

Using formula $\int e^{ax} dx=\frac{e^{ax}}{a}+C$

$\frac{xe^{7x}}{7}-\frac{1}{7}\int e^{7x}dx=-e^{-t}+C$

$\frac{xe^{7x}}{7}-\frac{1}{49}e^{7x}+e^{-t}=C$

$\frac{1}{49}(7x-1)e^{7x}+e^{-t}=C$

We are given that

$F(x,t)=C$

$F(x,t)=\frac{1}{49}(7x-1)e^{7x}+e^{-t}=C$

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3 years ago