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2 years ago

Twice the difference of a number and 1 is 4 more than that number. Find the numbers using Polyas 4 step

Mathematics

1 answer:

const2013 [10]2 years ago

4 0

Answer:

Step-by-step explanation:

2 times the difference of a number and 1 = 4 plus that number

In other to express the word problem Mathematically ; let the number = x

2(x - 1) = 4 + x

Expand

2x - 2 = 4 + x

Collect like terms

2x - x = 4 + 2

x = 6

Hence, the number is 6

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Help me with this please

rjkz [21]

X=9x y=-2 and the rest is filled in

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3 years ago

The average mark of candidates in an aptitude test was 128.5 with a standard deviation of 8.2.Three scores extracted from the te

Luba_88 [7]

Answer:

102

Step-by-step explanation:

We have the mean (m) 128.5 and the standard deviation (sd) 8.2, we must calculate the value of z for each one and determine whether or not it is an outlier:

z = (x - m) / sd

In the first case x = 148:

z = (148 - 128.5) /8.2

z = 2.37

In the second case x = 102:

z = (102 - 128.5) /8.2

z = -3.23

In the first case x = 152:

z = (152 - 128.5) /8.2

z = 2.86

The value of this is usually between -3 and 3, therefore when x is 102 it goes outside the range of the value of z, which means that this is the outlier.

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3 years ago

Occasionally an airline will lose a bag. Suppose a small airline has found it can reasonably model the number of bags lost each

julia-pushkina [17]

Answer:

a) The probability that the airline will lose no bags next monday is 0.1108

b) The probability that the airline will lose 0,1, or 2 bags next Monday is 0.6227

c) I would recommend taking a Poisson model with mean 4.4 instead of a Poisson model with mean 2.2

Step-by-step explanation:

The probability mass function of X, for which we denote the amount of bags lost next monday is given by this formula

$P(X=k) = \frac{e^{-2.2} * {2.2}^k }{k!}$

$P(X=0) = \frac{e^{-2.2} * {2.2}^0 }{0!} = 0.1108$

The probability that the airline will lose no bags next monday is 0.1108.

b) Note that $P(X \in \{0,1,2\} = P(X=0) + P(X=1) + P(X=2)$ . And

$P(X=0)+P(X=1)+P(X=2) = e^{-2.2} * (1 + 2.2 + 2.2^2/2) = 0.6227$

Therefore, the probability that the airline will lose 0,1, or 2 bags next Monday is 0.6227.

c) If the double of flights are taken, then you at least should expect to loose a similar proportion in bags, because you will have more chances for a bag to be lost. WIth this in mind, we can correctly think that the average amount of bags that will be lost each day will double. Thus, i would double the mean of the Poisson model, in other words, i would take a Poisson model with mean 4.4, instead of 2.2.

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3 years ago

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3 years ago

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romanna [79]

Answer:

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Step-by-step explanation:

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3 years ago