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mario62 [17]
2 years ago
11

Heptagon octagon nonagon

Mathematics
1 answer:
Elodia [21]2 years ago
7 0
The answer would for the problem would be 13
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Select the correct answer.
gizmo_the_mogwai [7]

Answer:

Factors are (x-1), (x+1), and (x+2).

Step-by-step explanation:

g(x)=x^{3}+2x^{2} -x-2\\g(x)=(x - 1) (x + 1) (x + 2)

7 0
3 years ago
Evaluate 2b^2-4a+4a^2 for a= 3 and b= -8
masha68 [24]
Given a = 3 and b = - 8 ,


= > 2b² - 4a + 4a²

= > 2( - 8 )² - 4( 3 ) + 4( 3 )²

= > 2( 64 ) - 4( 3 ) + 4( 9 )

= > 128 - 12 + 36

= > 116 + 36

= > 152



\:


5 0
3 years ago
Read 2 more answers
#54 Simplify and write the answers using positive exponents only.
kramer
Gg easy

remember
(x^m)/(x^n)=x^(m-n)
and
(x^m)^n=x^(mn)
and
(xyz)^m=(x^m)(y^m)(z^m)
and
(m/n)^a=(m^a)/(n^a)
and
x^-n=1/(x^n)

so
( \frac{6mn^{-2}}{3m^{-1}n^2} )^{-3}=
( \frac{6}{3} )^{-3}( \frac{m}{m^{-1}} )^{-3}( \frac{n^{-2}}{n^2} )^{-3}=
(2^{-3})((m^2)^{-3})((n^{-4})^{-3})=
( \frac{1}{2^3})(m^{-6})(n^{12})=
( \frac{1}{8} )( \frac{1}{m^6})(n^{12})=
\frac{n^{12}}{8m^6}

8 0
3 years ago
What is the sum of the prime factors of 2014
goblinko [34]

The sum of prime factors of 2014 is 74

<h3><u>Solution:</u></h3>

Given that to find sum of prime factors of 2014

Let us first find the prime factors of 2014

A prime number is a whole number greater than 1 whose only factors are 1 and itself

"Prime Factorization" is finding which prime numbers multiply together to make the original number.

<em><u>Prime factors of 2014:</u></em>

The Prime Factorization is:

2014 = 2 \times 19 \times 53

Thus the prime factors of 2014 are 2, 19, 53

<em><u>Let us now find the sum of prime factors of 2014</u></em>

sum of prime factors of 2014 = 2 + 19 + 53 = 74

Thus the sum of prime factors of 2014 is 74

7 0
3 years ago
30 points Help ASAP How do division properties help you evaluate expressions? Drag a word or number to the box to correctly comp
yKpoI14uk [10]

Answer:

Numerator , 0

Anything divided by 0 is always 0

Brainliest Pls

3 0
3 years ago
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