Step-by-step explanation:
Note: Question does not indicate if probability required is for weight to exceed or below 3000 lbs. So choose appropriate answer accordingly (near the end)
Using the usual notations and formulas,
mean, mu = 3550
standard deviation, sigma = 870
Observed value, X = 3000
We calculate
Z = (X-mu)/sigma = (3000-3550)/870 = -0.6321839
Probability of weight below 3000 lbs
= P(X<3000) = P(z<Z) = P(z<-0.6321839) = 0.2636334
Answer:
Probability that a car randomly selected is less than 3000
= P(X<3000) = 0.2636 (to 4 decimals)
Probability that a car randomly selected is greater than 3000
= 1 - P(X<3000) = 1 - 0.2636 (to 4 decimals) = 0.7364 (to 4 decimals)
Answer:
a) 37
b) 9
Step-by-step explanation:
(The input) × 5 - 3 = (The output)
When the input is 8,
8 × 5 - 3
= 40 - 3
= 37
When the output is 42.
(The input) × 5 - 3 =42
(The input) × 5 = 42 + 3
(The input) × 5/5=45/5
(The input) = 9
The input was 9.
So,
When rounding to the nearest thousand, look at the number in the hundreds place. If it is greater than or equal to 5, round up. If not, round down.
256,035
The hundreds place is less than 5, so we round down.
256,035 --> 256,000
Answer:
f(x)
Step-by-step explanation:
f(x)=x-1/x+5
y=x-1/x+5
xy+5y=x-1
xy-x=-1-5y
x(y-1)=1-5y
x=-1-5y/y-1
x=-5
So to begin your problem, you know that your car already has an average which is 65km/45 mins. The problem wants you to change this to km/hr. This means that you need to convert minutes to hours. A simple way to do this is by using fractions.
Set your problem up with fractions similar to this:
65km/45 mins x 60 mins/1 hr.
the whole point is to cancel out your minutes, and leave the hours as your new unit for the denominator
65km/45 x 60/1 hr.
now you want to reduce (I divided the first fraction by 5)
13km/9 x 60/1 hr.
780km/9hrs.
That would be your answer. If someone can double check my math that would be fantastic.
