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3 years ago

Tell whether -2 is a solution of the intequality. 8-2x<12

Mathematics

1 answer:

Llana [10]3 years ago

6 0

Answer:

add 8 to 2 and then multiply the 8 with 12.

Step-by-step explanation:

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In which quadrant is the number –14 – 5i located on the complex plane?

AlekseyPX

On the complex plane, the real component of a complex number is graphed along the horizontal axis while the imaginary component is graphed along the vertical axis.

Positive numbers go to the right on the real axis and up on the imaginary axis, and vice versa for negative numbers.

Therefore, the number -14-5i is in the 3rd quadrant because it graphed to the left of the origin and down.

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3 years ago

1. It took Joseph 10 days, 21 hours, and 30 minutes to get from San Diego to Boston. How many hours did it take him? Show your w

RUDIKE [14]

1) cf= 24 hours/1 day, 1 hour/60 minutes
30 x 1/60 = .5
10 x 24/1 = 240
240 + .5 = 240.5 hours

2) cf = 24 hours/1 day, 60 minutes/1 hour, 12 inches/1 foot
a) 0.6 x 12/1 = 7.2 inches
b) 7.2 x 1/24 = 0.3 inches per hour

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4 years ago

The sum of double a number and 8

olya-2409 [2.1K]

The answer is 10...............

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3 years ago

Write 270 as a product of its prime factors

marshall27 [118]

$270 = 90 \times 3 \\\\ = 3\times 3\times 5\times 2\times 3\\\\= \boxed{\bf{2\times 3^3 \times 5}}$

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3 years ago

The circumference of a sphere was measured to be 76 cm with a possible error of 0.5 cm. (a) Use differentials to estimate the ma

andreev551 [17]

The maximum error in the calculated surface area is 24.19cm² and the relative error is 0.0132.

Given that the circumference of a sphere is 76cm and error is 0.5cm.

The formula of the surface area of a sphere is A=4πr².

Differentiate both sides with respect to r and get

dA÷dr=2×4πr

dA÷dr=8πr

dA=8πr×dr

The circumference of a sphere is C=2πr.

From above the find the value of r is

r=C÷(2π)

By using the error in circumference relation to error in radius by:

Differentiate both sides with respect to r as

dr÷dr=dC÷(2πdr)

1=dC÷(2πdr)

dr=dC÷(2π)

The maximum error in surface area is simplified as:

Substitute the value of dr in dA as

dA=8πr×(dC÷(2π))

Cancel π from both numerator and denominator and simplify it

dA=4rdC

Substitute the value of r=C÷(2π) in above and get

dA=4dC×(C÷2π)

dA=(2CdC)÷π

Here, C=76cm and dC=0.5cm.

Substitute this in above as

dA=(2×76×0.5)÷π

dA=76÷π

dA=24.19cm².

Find relative error as the relative error is between the value of the Area and the maximum error, therefore:

$\begin{aligned}\frac{dA}{A}&=\frac{8\pi rdr}{4\pi r^2}\\ \frac{dA}{A}&=\frac{2dr}{r}\end$

As above its found that r=C÷(2π) and r=dC÷(2π).

Substitute this in the above

$\begin{aligned}\frac{dA}{A}&=\frac{\frac{2dC}{2\pi}}{\frac{C}{2\pi}}\\ &=\frac{2dC}{C}\\ &=\frac{2\times 0.5}{76}\\ &=0.0132\end$

Hence, the maximum error in the calculated surface area with the circumference of a sphere was measured to be 76 cm with a possible error of 0.5 cm is 24.19cm² and the relative error is 0.0132.

Learn about relative error from here brainly.com/question/13106593

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2 years ago