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never [62]
3 years ago
7

On a normal day, I can walk from my house to school in three quarters of an hour. The return trip takes me the same amount of ti

me. My mom, driving our car, covers that distance in about a quarter of the time that it takes me. If I go to school five days a week and there are thirty-seven weeks in the school year,
how many hours would I save every year if my mom agreed to drive me to and from school?
Give your answer as a mixed number.
Mathematics
1 answer:
Likurg_2 [28]3 years ago
4 0

Answer:

  208 1/8 hours

Step-by-step explanation:

The amount of time saved on each trip is ...

  (3/4 h) - (1/4)(3/4 h) = (3/4)(3/4 h) = 9/16 h

There are 2×5×37 = 370 trips in the school year, so the total savings in time is about ...

  370×(9/16 h) = 208 1/8 h

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2 Here are two equations:
MatroZZZ [7]

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Step-by-step explanation:

a. Decide whether each neither of the equations,

i (3,4)

ii. (4,2.5)

ill. (5,5)

iv. (3,2)

To decide whether each point is solution to equations or not we will put the point in the equations

Equations are:

Equation 1: 6x + 4y = 34

Equation 2: 5x – 2y = 15

<u>i (3,4) </u>

Putting in Equation 1:

6(3) + 4(4) = 34\\18+16=34\\34=34\\

Putting in Equation 2:

5(3) - 2(4) = 15\\15-8 = 15\\7\neq 15

<u>ii. (4,2.5)</u>

Putting in Equation 1:

6(4) + 4(2.5) = 34\\24+10=34\\34=34\\

Putting in Equation 2:

5(4) - 2(2.5) = 15\\20-5 = 15\\15=15

<u>ill. (5,5)</u>

6(5) + 4(5) = 34\\30+20=34\\50\neq 34

Putting in Equation 2:

5(5) - 2(5) = 15\\25-10 = 15\\15=15

<u>iv. (3,2)</u>

6(3) + 4(2) = 34\\18+8=34\\26\neq 34

Putting in Equation 2:

5(3) - 2(2) = 15\\15-4 = 15\\11\neq 15

Hence,

(3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. Is it possible to have more than one (x, y) pair that is a solution to both

equations?

The simultaneous linear equations' solution is the point on which the lines intersect. Two lines can intersect only on one point. So a linear system cannot have more than one point as a solution

So,

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Keywords: Linear equations, Ordered pairs

Learn more about linear equations at:

  • brainly.com/question/10534381
  • brainly.com/question/10538663

#LearnwithBrainly

8 0
3 years ago
What is the rate of change of the function?
scoundrel [369]

Answer:

rate of change = 3

Step-by-step explanation:

to find the rate of change \frac{y1 - y2}{x1 - x2}

(0,-4) (1,-1)

\frac{-4+1}{0-1} = \frac{-3}{-1} = 3

7 0
3 years ago
Read 2 more answers
What is the value of 7^2-3^3
lbvjy [14]

Answer:

22

Step-by-step explanation:

7^2-3^3

(7)(7)-(3)(3)(3)

49-(3)(9)

49-27

22

3 0
2 years ago
If 2p + p = 20 then what is 2p - 5 =
Wewaii [24]
Ok first we have to find out whats 2p+p=20 combine like terms to get 3p=20 the divide 3 on each side to get p=6 2/3 then we plug in 6 2/3 to 2p-5 so 2(6 2/3) -5 so its 12.666-5 to get 7.666 so that's the answer.
4 0
2 years ago
Question 1 (2 points)
andrew-mc [135]

Answer:8

Step-by-step explanation:

8 0
3 years ago
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