Question

B^2-4b+4=0 Quadratic formula

Answer 1

$b^2-4b+4=0 \\ \\ b = \frac{-(-4) \pm \sqrt{(-4)^2 - 4(1)(4)} }{2(1)} \\ \\ b = \frac{-(-4)}{2(1)} \\ \\ b = 2$

The final result is: b = 2.