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malfutka [58]
3 years ago
9

© Write a Pythagorean triplet whose one member is 50

Mathematics
1 answer:
KIM [24]3 years ago
5 0

Answer:

Thus the required Pythagorean triplet is 14,48,50. ∴ The required Pythagorean triplet is 16,63,65.

Step-by-step explanation:

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no

Step-by-step explanation:

1.  what is this supposed to mean

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The answer is 40. All we have to do is find the number of 16 year olds who spent between 25-35 minutes in social media. That is 145. The number of 13 year olds who spent the same amount of time is only 105, therefore 40 more 16 year olds spent between 25 and 35 minutes on social media.
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What is the inverse of f(x) = 19/x^3
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Y = f (x) = 19 / x^3 and g (y) = x 
<span>g is inverse of f </span>

<span>x^3 = 19 / y </span>
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3 years ago
Solve 2x&lt;10. Explain how to find the solution set.
victus00 [196]

Answer:

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Step-by-step explanation:

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7 0
2 years ago
Read 2 more answers
Suppose data made available through a health system tracker showed health expenditures were $10,348 per person in the United Sta
nignag [31]

Answer:

a) 30.08% probability the sample mean will be within $100 of the population mean.

b) 0% probability the sample mean will be greater than $12,600

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the Central Limit Theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 10348, \sigma = 2500, n = 100, s = \frac{2500}{\sqrt{100}} = 250

a. What is the probability the sample mean will be within ±$100 of the population mean?

This is the pvalue of Z when X = 100 divided by s subtracted by the pvalue of Z when X = -100 divided by s. So

Z = \frac{100}{250} = 0.4

Z = -\frac{100}{250} = -0.4

Z = 0.4 has a pvalue of 0.6554, Z = -0.4 has a pvalue of 0.3556

0.6554 - 0.3546 = 0.3008

30.08% probability the sample mean will be within $100 of the population mean.

b. What is the probability the sample mean will be greater than $12,600?

This is 1 subtracted by the pvalue of Z when X = 12600. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{12600 - 10348}{250}

Z = 9

Z = 9 has a pvalue of 1.

1 - 1 = 0

0% probability the sample mean will be greater than $12,600

5 0
2 years ago
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