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uranmaximum [27]

2 years ago

15

PLEASE HELP!!!!! 2.) What is the perimeter of a polygon with vertices at (-3, 1), (5, 1), (-3, 4), (5, 4)? 30 points if you can

help

1 answer:

vredina [299]2 years ago

4 0

Answer:

22 units

Step-by-step explanation:

Known Quantities:

AB = CD and AC = BD

Calculations:

AB = 8
AC = 3
CD = 8
BD = 3

Final Calculations:

perimeter = 2 x (3+8)
perimeter = 22

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Perform the indicated row operations, then write the new matrix.

Studentka2010 [4]

The matrix is not properly formatted.

However, I'm able to rearrange the question as:

$\left[\begin{array}{ccc}1&1&1|-1\\-2&3&5|3\\3&2&4|1\end{array}\right]$

Operations:

$2R_1 + R_2 ->R_2$

$-3R_1 +R_3 ->R_3$

Please note that the above may not reflect the original question. However, you should be able to implement my steps in your question.

Answer:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

Step-by-step explanation:

The first operation:

$2R_1 + R_2 ->R_2$

This means that the new second row (R2) is derived by:

Multiplying the first row (R1) by 2; add this to the second row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by 2

$2 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}2&2&2|-2\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}2&2&2|-2\end{array}\right] + \left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}0&5&7|1\end{array}\right]$

The second operation:

$-3R_1 +R_3 ->R_3$

This means that the new third row (R3) is derived by:

Multiplying the first row (R1) by -3; add this to the third row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by -3

$-3 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right] + \left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}0&-1&1|4\end{array}\right]$

Hence, the new matrix is:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

3 0

3 years ago

Read 2 more answers

Find the probability of at least 6 failures in 7 trials of a binomial experiment in which the probability of success in any one

oksano4ka [1.4K]

Answer:

$P(x \geq 6)=P(X=6)+P(X=7)$

And we can find the individual probabilities:

$P(X=6)=(7C6)(0.91)^6 (1-0.91)^{7-6}=0.358$

$P(X=7)=(7C7)(0.91)^7 (1-0.91)^{7-7}=0.517$

And replacing we got:

$P(x \geq 6)=P(X=6)+P(X=7)= 0.358+0.517=0.875$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=7, p=1-0.09=0.91)$

The probability associated to a failure would be p =1-0.09 = 0.91

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want to find this probability:

$P(x \geq 6)=P(X=6)+P(X=7)$

And we can find the individual probabilities:

$P(X=6)=(7C6)(0.91)^6 (1-0.91)^{7-6}=0.358$

$P(X=7)=(7C7)(0.91)^7 (1-0.91)^{7-7}=0.517$

And replacing we got:

$P(x \geq 6)=P(X=6)+P(X=7)= 0.358+0.517=0.875$

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Simplify the expression<br> 6x + 2x =

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the answer should be 8x

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What is 23.5 in word form

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To hundred three hundred and five

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What is an expression that is equivalent to 3x-3y

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3x-3y+0+1-1 Just tack on something onto it that doesn't change the outcome

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