1.) The interval of the value of x is from -5 to 1, inclusive. Remember that what is asked is the absolute value, thus the sign does not matter even if you have to subtract x from 5. Thus, the maximum value would be obtained if the x is smaller, which is 1. The minimum value is obtained when x=-5.
Absolute maximum value:
x = - 5f(-5) = ║5 - 7(-5)^2║ = ║-170║=
170Absolute minimum value:
x = 1f(1) = ║5 - 7(1)^2║ = ║-2║=
2
2.) The Mean Value Theorem (MVT) applies to functions that are continuous and differentiable on the closed and open interval of a to b, respectively. Since the function is a quadratic function, MVT can be applied. Then, this means that there is a value of c which is between a and b. This could be determined using this formula according to MVT:
The differentiated form would be f'(x) = -2x. Then,
Thus, x = -1, x = -1/2, and x=0 all lie in the function 4-x^2.
Answer:
Has two unkown variables
Step-by-step explanation:
When there is only one equation provided with two unknown variables, it is difficult to solve for the unknown variables
The most simplified version of this equation would be VX = -14
More information would be needed to solve
Answer:
2/3, 3/4, 5/6, 7/8, 8/9, 9/10, etc.
Step-by-step explanation:
1/2 is smaller than 1/3, which is smaller than 3/4, which is in turn smaller than 5/6, and so on.
Answer:36.5625
Step-by-step explanation:
Hope this helped!
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