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Dima020 [189]
3 years ago
7

In what form is the following linear equation written?

Mathematics
1 answer:
krok68 [10]3 years ago
5 0

Answer:

<h2>B. Standard</h2>

Step-by-step explanation:

The point-slope form of an equation of a line:

y-y_1=m(x-x_1)

m - slope

(x₁, y₁) - point

The slope-intercept form of an equation of a line:

y=mx+b

m - slope

b - y-intercept

The standard form of an equation of a line:

Ax+By=C

The general fom of an equation of a line:

Ax+By+C

We have the equation 3x - 2y = 4 in standard form.

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What is the length of the altitude of the equilateral triangle below?​
ElenaW [278]

Answer:

A

Step-by-step explanation:

the height a creates with half of the baseline (5) and a leg (10) a right-angled triangle, and we can use Pythagoras to calculate a.

c² = a² + b²

c being the Hypotenuse (the side opposite of the 90° angle, so in our case the 10 side).

10² = a² + 5²

100 = a² + 25

75 = a²

a = sqrt(75) = sqrt(3×25) = 5×sqrt(3)

5 0
2 years ago
D is the midpoint of CE. If CD= 2x+10 and DE =3x-18, find x and CE<br><br> x=<br> CE=
Veseljchak [2.6K]

Answer:

<h2>x = 28</h2><h2>CE = 132</h2><h2 />

Step-by-step explanation:

|<------------- CE -------------------->|

C-------------------D-------------------E

       2x + 10              3x - 18

2x + 10 = 3x - 18

2x - 3x = -18 - 10

-x = -28

x = 28

CE = 2x + 10 + 3x - 18

CE = 2(28) + 10 + 3(28) - 18

CE = 56 + 10 + 84 - 18

CE = 132

3 0
3 years ago
Find the product.
4vir4ik [10]
Answer :

6{y}^{4} {z}^{2} + 12 {y}^{3} {z}^{2}-3 {y}^{3} {z}+3 {y}^{2} {z}^{2}

Step-by-step explanation :

To find the product of

3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)

First we expand the bracket ,

it implies that, we use the expression outside the bracket to multiply individual expressions inside the bracket.

Hence

3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)

= 3 {y}^{2} z(2 {y}^{2} z) + 3 {y}^{2} z(4yz) - 3 {y}^{2} z(y )+3 {y}^{2} z( z)

we now apply the law of indices

{a}^{m} \times {a}^{n} = {a}^{m+n}

meaning, when you are multiplying two expressions with the same bases , repeat one of the bases and add the exponents.

Then, simplify to obtain

= 6{y}^{4} {z}^{2} + 12 {y}^{3} {z}^{2}-3{y}^{3} {z}+3 {y}^{2} {z}^{2}
3 0
3 years ago
Find the volume to the nearest hunkeredth
Over [174]

Step-by-step explanation:

rjrurjrrmrjrjrnrbrbdu

5 0
3 years ago
3x+1 = y 2x+3y = 14<br> please explain the steps if you can as well
Likurg_2 [28]
3x + 1 = y
2x + 3y = 14

To solve this system of equations, we are going to use the substitution method.  Substitution the equation where the variable is isolated into the second equation.  In this system of equations, y is isolated, so we will replace y in the second equation with 3x + 1.

2x + 3y = 14
2x + 3(3x + 1) = 14
2x + 9x + 3 = 14
We will add the like terms and subtract 3 from both sides of the equation.
11x + 3 = 14
11x = 11
x = 1
In this system of equations, x is equal to 1.  Now we will go back and solve for y, plugging in 1 for x.
3(1) + 1 = y
2(1) + 3y = 14

3 + 1 = y
2 + 3y = 14

4 = y
3y = 2

4 = y
4 = y

The solution to this system of equations is (1, 4).

8 0
3 years ago
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