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3 years ago

What is the product of the perpendicular lines

Mathematics

2 answers:

sattari [20]3 years ago

5 0

Answer:

-1 i think

Step-by-step explanation:

Andrews [41]3 years ago

4 0

Answer: Multiply the slopes of two perpendicular lines in the plane, you get −1

Step-by-step explanation: Slopes of perpendicular lines are opposite reciprocals. you can't multiply their slopes, since the slope of a vertical line is undefined.

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Find the missing supplementary angle.

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Recall that the formula for the circumference of a circle is C = 2piR. The radius is 3 (half of 6, the diameter). 2*pi*3 is 6pi, which is approximately 19 inches.

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4 years ago

.What is the value of the expression 6m + m - 4(-2m + 1 - m) when m = -8

aev [14]

6m + m - 4(-2m + 1) - m = 7m + 8m - 4 - m = 15m - 4 - m = 14m - 4

put m = -8 to the expresiion:

14(-8) - 4 = -112 - 4 = -116

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3 years ago

3. Make a class frequency table using 2 rule of the following data. Find the Mean and make a Cumulative frequency Histogram [10]

sashaice [31]

Answer: Mean = 284

Step-by-step explanation:

Data:

125, 126, 127, 127, 137

201, 202, 207, 211, 215, 218, 224, 237, 261

301, 308, 310, 315, 330, 330, 360, 380, 393, 394

401, 401, 410, 421, 422, 424

Class Frequency Table:

$\boxed{\begin{array}{c|c|c}\underline{\text{Intervals}}&\underline{\text{\qquad Frequency\qquad}}&\underline{\text{Cumulative Frequency}}\\0-49&0&0\\50-99&0&0\\100-149&5&5\\150-199&0&5\\200-249&8&13\\250-299&1&14\\300-349&6&20\\350-399&4&24\\400-449&6&30\\450-499&0&30\end{array}}\\.\qquad \qquad \qquad \qquad \quad \ 30$

Mean:

The sum of the numbers divided by the quantity of numbers:

8518/30 = 283.933

Cumulative Frequency Histogram:

Create the graph based on the Interval and Cumulative Frequency of the class frequency table above. (see image)

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4 years ago

Find the constant proportionality: y=1/4x

insens350 [35]

Answer:

is k4

Step-by-step explanation:

the standard equation representing direct variation is

∙

←

k is the constant of variation

is in this form

⇒

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4 years ago

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