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3 years ago

Help Me Please Im getting frustrated with this

Mathematics

1 answer:

omeli [17]3 years ago

8 0

It will take about 19 to 20 year for the tree to grow 20 feet

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Margo is creating a pencil caddy in the shape of a triangular prism. She is determining how much wood she needs to build the cad

natka813 [3]

Answer:

a little late

205 1/5 is your answer

Step-by-step explanation:

break down the 3-D figure

Find area of triangle A=1/2bh

=1/2(8 inch)(6 9/10inch)

=1/2(8 inch)(69/10 inch)

=138/5 square inch

then multiply two because you have 2 triangles

=138/5 (2)

= 276/5 square inch

= 55 1/5 sq.in

Find area of rectangle

A = lw

=6 1/4 in (8 in)

= 25/4 (8 in.)

= 50 sq. in.

then multiply by 3 because of the three rectangles

= 50 sq. inch (3)

= 150 sq. in.

Add all together

55 1/5 sq. inch + 150 sq. inch = 205 1/5 sq. inch

4 0

3 years ago

Yuhhhhhhhhhhhhhhhhh

Mashutka [201]

Answer:

6. 550

7. 70

Step-by-step explanation:

6. 16+28 = 44, 44*25 = 1100 divided by 2 = 550

7. 2.5+3+5.5 = 11, 11+3 = 14, 14*10 = 140 divided by 2 = 70

3 0

3 years ago

Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 144 millimeters,

valentinak56 [21]

Answer:

The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

$\mu_{\bar x}=\mu$

And the standard deviation of the distribution of sample mean is given by,

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}$

The information provided is:

μ = 144 mm

σ = 7 mm

n = 50.

Since n = 50 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample mean.

$\bar X\sim N(\mu_{\bar x}=144, \sigma_{\bar x}^{2}=0.98)$

Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:

$P(\bar X-\mu_{\bar x}>2.6)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}} >\frac{2.6}{\sqrt{0.98}})$

$=P(Z>2.63)\\=1-P(Z$

*Use a z-table for the probability.

Thus, the probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

8 0

3 years ago

Pls answer this 5 and _____ are reciprocal numbers.

Jet001 [13]

Answer:

1/5

Step-by-step explanation:

Reciprocal just means flipped you can put any whole number over 1 if it helps to see that

5/1 = 5

Since reciprocal is asking you to flip 5/1 meaning numerator becomes denominator and vice versa you end up with 1/5 being the reciprocal of 5

6 0

3 years ago

Deb Boon is single, claims 2 allowances and earns $293.23 each week. If each weekly allowance is $63.46, how much is Deb's taxab

Nesterboy [21]

None, because you need to make over 15,000 a year to be taxed. And with all that money for one year would not be taxed.

6 0

3 years ago