no this relation is not a function, because for each input (x), there is no output (y)
Answer:
4
Explanation:
y ¤ x...where ¤ represents the Greek alpha sign...
y = k • x
-8 = -2 • x
-8/-2 = x
4 = x
(x-3)^2=5=>
(x-3)=±square root of 5
x=+sqr.root5+3 or x=-sqr.root5+3
