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Levart [38]
3 years ago
13

Answer both questions please :D

Mathematics
2 answers:
ikadub [295]3 years ago
6 0
Im only responding for points sorry-
ICE Princess25 [194]3 years ago
3 0

Answer:

The first relation is a function because each input only has one output. The second relation is not a function because each output is shared by multiple inputs.

Step-by-step explanation:

Hope this helps :)

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Write 2 other expressions equivalent to 4x + 4y <br> PLZ ANSWER FAST THANK YOU
hram777 [196]
2(2x +2y) and <span>√(4x + 4y)^2</span>
7 0
4 years ago
Differential Equation
ANEK [815]

1. The given equation is probably supposed to read

y'' - 2y' - 3y = 64x exp(-x)

First consider the homogeneous equation,

y'' - 2y' - 3y = 0

which has characteristic equation

r² - 2r - 3 = (r - 3) (r + 1) = 0

with roots r = 3 and r = -1. Then the characteristic solution is

y = C_1 e^{3x} + C_2 e^{-x}

and we let y₁ = exp(3x) and y₂ = exp(-x), our fundamental solutions.

Now we use variation of parameters, which gives a particular solution of the form

y_p = u_1y_1 + u_2y_2

where

\displaystyle u_1 = -\int \frac{64xe^{-x}y_2}{W(y_1,y_2)} \, dx

\displaystyle u_2 = \int \frac{64xe^{-x}y_1}{W(y_1,y_2)} \, dx

and W(y₁, y₂) is the Wronskian determinant of the two fundamental solutions. This is

W(y_1,y_2) = \begin{vmatrix}e^{3x} & e^{-x} \\ (e^{3x})' & (e^{-x})'\end{vmatrix} = \begin{vmatrix}e^{3x} & e^{-x} \\ 3e^{3x} & -e^{-x}\end{vmatrix} = -e^{2x} - 3e^{2x} = -4e^{2x}

Then we find

\displaystyle u_1 = -\int \frac{64xe^{-x} \cdot e^{-x}}{-4e^{2x}} \, dx = 16 \int xe^{-4x} \, dx = -(4x + 1) e^{-4x}

\displaystyle u_2 = \int \frac{64xe^{-x} \cdot e^{3x}}{-4e^{2x}} \, dx = -16 \int x \, dx = -8x^2

so it follows that the particular solution is

y_p = -(4x+1)e^{-4x} \cdot e^{3x} - 8x^2\cdot e^{-x} = -(8x^2+4x+1)e^{-x}

and so the general solution is

\boxed{y(x) = C_1 e^{3x} + C_2e^{-x} - (8x^2+4x+1) e^{-x}}

2. I'll again assume there's typo in the equation, and that it should read

y''' - 6y'' + 11y' - 6y = 2x exp(-x)

Again, we consider the homogeneous equation,

y''' - 6y'' + 11y' - 6y = 0

and observe that the characteristic polynomial,

r³ - 6r² + 11r - 6

has coefficients that sum to 1 - 6 + 11 - 6 = 0, which immediately tells us that r = 1 is a root. Polynomial division and subsequent factoring yields

r³ - 6r² + 11r - 6 = (r - 1) (r² - 5r + 6) = (r - 1) (r - 2) (r - 3)

and from this we see the characteristic solution is

y_c = C_1 e^x + C_2 e^{2x} + C_3 e^{3x}

For the particular solution, I'll use undetermined coefficients. We look for a solution of the form

y_p = (ax+b)e^{-x}

whose first three derivatives are

{y_p}' = ae^{-x} - (ax+b)e^{-x} = (-ax+a-b)e^{-x}

{y_p}'' = -ae^{-x} - (-ax+a-b)e^{-x} = (ax-2a+b)e^{-x}

{y_p}''' = ae^{-x} - (ax-2a+b)e^{-x} = (-ax+3a-b)e^{-x}

Substituting these into the equation gives

(-ax+3a-b)e^{-x} - 6(ax-2a+b)e^{-x} + 11(-ax+a-b)e^{-x} - 6(ax+b)e^{-x} = 2xe^{-x}

(-ax+3a-b) - 6(ax-2a+b) + 11(-ax+a-b) - 6(ax+b) = 2x

-24ax+26a-24b = 2x

It follows that -24a = 2 and 26a - 24b = 0, so that a = -1/12 = -12/144 and b = -13/144, so the particular solution is

y_p = -\dfrac{12x+13}{144}e^{-x}

and the general solution is

\boxed{y = C_1 e^x + C_2 e^{2x} + C_3 e^{3x} - \dfrac{12x+13}{144} e^{-x}}

5 0
3 years ago
10. RP3-M
SashulF [63]

Answer:

Jeannette's ticket was less than the original pice by 30%

Step-by-step explanation:

original price = $75

percentage discount = 20% of original price = 20% of $75

discounted price = \frac{20}{100} \times\ 75\ =\ 15

discounted price = $15

website service fee = 10% of original price

website service fee = \frac{10}{100}\times 75 = \$7.5

New discounted price = discount price + website service fee

= 15 + 7.5 = $22.5

Next, let us calculate what percentage of the original price that will give the new discount price.

Let the percentage of the original price = x%

x% of 75 = $22.5

\frac{x}{100} \times\ 75\ = 22.5\\\\\frac{75x}{100} = 22.5\\\\75x = 2250\\\\x = \frac{2250}{75} \\\\x = 30

Therefore, Jeannette's ticket was less than the original pice by 30%

5 0
3 years ago
Please give an answer and solution.
kvv77 [185]

Using proportions, it is found that 78 students would prefer long jump.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

Out of 300 students, 26% would prefer long jump, hence the amount is given by:

n = 0.26 x 300 = 78 students.

More can be learned about proportions at brainly.com/question/24372153

#SPJ1

8 0
2 years ago
Which equation represents the line that passes through (-3,5) and is parallel to the graph of y= -2/3x+5
Nostrana [21]
Parallel to the graph of y = -2/3x + 5
means that it has the same slope

Rewrite
y = -2/3x + b
plug in the given coordinates to solve for b
5 = -2/3(-3) + b
5 = 2 + b
subtract 2 from both sides
3 = b

plug that back into the equation
y = -2/3x + b
y = -2/3x + 3

The answer is <span>B. y= -2/3x+3</span>

This line is parallel to y = -2/3x + 5 and it passes the point (3, 5).

Hope this helps :)
4 0
3 years ago
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