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AlladinOne [14]
3 years ago
14

What is 8q+12=4(3+3q)

Mathematics
2 answers:
Alex17521 [72]3 years ago
6 0

Answer:

Q = 0

Step-by-step explanation:

1. Expand.

8q + 12 = 12 + 12q

2.cancle 12 on both sides.

8q = 12q

3. Move all terms to one side.

8q - 12q = 0

4. simplify 8q - 12q to -4q.

-4q = 0

5. Divide both sides by -4.

q=0

therefor, the answer is q=0

Elena-2011 [213]3 years ago
4 0

Answer:

q = 0

Step-by-step explanation:

8q + 12 = 4( 3 + 3q )

Distributive property

8q + 12 = 4 ( 3 + 3q )

8q + 12 = 12 + 12q

Inverse operations

8q + 12 = 12 + 12q

-8q               -8q

12 = 12 + 4q

-12  -12

0 = q

q = 0

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kirill [66]

Answer:

<h3>A. 1 hour</h3>

Step-by-step explanation:

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3 0
3 years ago
Which ordered pair is a solution of the equation
andrew11 [14]
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(1,-7)
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-7 is not 15 ----not a solution

(2,26)
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4 0
4 years ago
The quotient of 3 and the cube<br> of y+2
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Answer:

  \dfrac{3}{(y+2)^3}

Step-by-step explanation:

Maybe you want this written using math symbols. It will be ...

  \boxed{\dfrac{3}{(y+2)^3}}

3 0
3 years ago
Help!! What is the point in the feasible region maximizes the objection function?
svlad2 [7]

First, find the vertices of the shaded region. You can do this my graphing or by solving a system of equations for each pair of functions. <em>I am going to find them by graphing.</em>

x ≥ 0 and y ≥ 0 place the shaded region in the first quadrant with a vertex at (0, 0)

now graph y ≤ 3.  a vertex is at (0, 3)

now graph y < -2x + 5. a vertex is at (1, 3). the other vertex is the x-intercept (when y = 0).

                  0 = -2x + 5

                  -5 = -2x

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Next, input the coordinates of the vertices into the objective function.

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             =          0

(0, 3): C = -6(0) + 5(3)

             =    0    +   15

             =          15

(1, 3): C = -6(1) + 5(3)

             =  -6  +  15

             =       9

(\frac{5}{2} , 0): C = -6(\frac{5}{2}[/tex]) + 5(2)

             =  -15  +  10

             =       -5

The maximum is C = 15 which occurs at vertex (0, 3)

Answer: A


                 


6 0
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