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2 years ago

Which expression is equivalent to -32^3/5?

Mathematics

1 answer:

Sunny_sXe [5.5K]2 years ago

4 0

Answer:

the first one

Step-by-step explanation:

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Match the following three dimensional figures to the appropriate nets below.

BartSMP [9]

Answer:

1) C

2) A

3) E

Step-by-step explanation:

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2 years ago

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Slope= -1/2, y-intercept = 4

navik [9.2K]

Answer:

y=-1/2x+4

Step-by-step explanation:

y=mx+b

where m=slope and b=y-intercept

y=-1/2x+4

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3 years ago

What's the common difference 6.5,5,3.5,2,

Zinaida [17]

1.5 because if u subtract 1.5 from each number u get the next number

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2 years ago

Evaluate: (d + 1)(d - 1 + 6) <br> d = 2

Allisa [31]

F(d)=(d+1)(d-1+6)
f(d)=(d+1)(d+5)
f(2)=(2+1)(2+5)
f(2)=(3)(7)
f(2)=21

3 0

2 years ago

A cup of coffee contains about 100 mg of caffeine. Caffeine is metabolized and leaves the body at a continuous rate of about 12%

Mamont248 [21]

Answer:

a. $A = C_{0}(1-x)^t\\x: percentage\ of \ caffeine\ metabolized\\$

b. $\frac{dA}{dt}= -11.25 \frac{mg}{h}$

Step-by-step explanation:

First, we need tot find a general expression for the amount of caffeine remaining in the body after certain time. As the problem states that every hour x percent of caffeine leaves the body, we must substract that percentage from the initial quantity of caffeine, by each hour passing. That expression would be:

$A= C_{0}(1-x)^t\\t: time \ in \ hours\\x: percentage \ of \ caffeine\ metabolized\\$

Then, to find the amount of caffeine metabolized per hour, we need to differentiate the previous equation. Following the differentiation rules we get:

$\frac{dA}{dt} =C_{0}(1-x)^t \ln (1-x)\\\frac{dA}{dt} =100*0.88\ln(0.88)\\\frac{dA}{dt} =-11.25 \frac{mg}{h}$

The rate is negative as it represents the amount of caffeine leaving the body at certain time.

3 0

3 years ago