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Vsevolod [243]
3 years ago
6

State the hundred thousands place for 7,832,906,215

Mathematics
1 answer:
juin [17]3 years ago
4 0

Answer:

Step-by-step explanation:

6 is the thousands place

0 (right next to it) is the 10 thousands place

9 is the hundred thousands place. There is only 1 nine present so the answer is unique.

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Use the Law of Cosines to find the missing angle. In triangle JKL, j=3in., k=4in., and l=2.89., find mJ
slega [8]
Using the law of cosine for Triangle KJL, we can write:

j^{2} = k^{2} + l^{2}-2(k)(l)cos(J)  \\  \\ 
2(k)(l)cos(J)=k^{2} + l^{2}- j^{2} \\  \\ 
cos(J)= \frac{k^{2} + l^{2}- j^{2}}{2(k)(l)}

Using the values of k,j and l, we can write:

cos(J)= \frac{ 4^{2} + (2.89)^{2} - 3^{2} }{2(4)(2.89)}  \\  \\ 
cos(J)= 0.664 \\  \\ 
J= cos^{-1}(0.664) \\  \\ 
J=48.39

Rounding to nearest integer, the measure of angle J will be 48 degrees.
So option B gives the correct answer
8 0
2 years ago
Read 2 more answers
The base of a right pyramid is a regular hexagon with sides of length 12 m. The altitude is 6 m. Find the total surface area of
Eva8 [605]

Answer:

806.12 m

Step-by-step explanation:

<u>Step 1: Write the data</u>

<em>Side (s) = 12</em>

<em>Altitude (h) = 6</em>

<u>Step 2: Write the formula for surface area of right hexagonal pyramid</u>

<em>Area = 3√3/2*s² + 3*s*√(h²+3s²/4)</em>

<u>Step 3: Substitute values of 's' and 'h'</u>

<em>Area = 3√3/2*(12)² + 3*(12)*√[6²+3(12)²/4]</em>

Area = 806.12 m

Therefore, the total surface area of the pyramid is 806.12 m.

!!

4 0
3 years ago
answer to #10 and #13. can’t figure out how to use interval notation to write domain and range for graphs.
Lyrx [107]
Interval notation is used to write a set of real numbers from one value to another value.
On the left, you start with left parenthesis or left bracket.
Then you follow by two numbers separated by a comma.
You then finish with a right parenthesis or right bracket.
To include a number, use a square bracket.
To exclude a number use parenthesis.
To write the set of numbers, you need to list the smallest number in the set followed by the largest number in the set. An interval is always stated with two numbers, from the smallest in the set to the largest in the set. The numbers are always separated by a comma.

Examples:

1) All numbers from 6 to 10, including 6 and 10.
Algebra: 6 <= x <= 10
Interval: [6, 10]
Notice brackets since both 6 and 10 are included in this interval.

2) All number from 5 to 20, including 5 but not including 20.
Algebra 5 <= x < 20
Interval: [5, 20)
Bracket with 5 means include 5. Parenthesis with 20 means 20 is not included.

3) All numbers greater than or equal to 7.
Algebra: x >= 7
Interval: [7, ∞)
The 7 has a bracket because it is included. Infinity always has parenthesis.
With the infinity symbol, always use parenthesis, not square bracket.

4) All numbers less than -5.
Algebra: x < - 5
Interval: (-∞, 5)

Now for your problems.

10.
This is a line. Both the domain and range all all real numbers.
That means the interval is from negative infinity to positive infinity.
(-∞, ∞)
Both the domain and range are that same interval, all real numbers, from negative infinity to positive infinity.

13.
The domain is all real numbers as you can see the x-coordinates extend left forever and right forever. The domain is the same interval as the domain and range of problem 10.

The range is zero and all positive numbers.
You can think of it a all values of y such that y is greater than or equal to zero. Notice that zero is included in the interval.

[0, ∞)

Since zero is included, we use a left bracket, not left parenthesis.
With infinity, we alyways use parentheses, not brackets.
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Х'y<br> 62<br> Use properties of exponents to simplify the expression.
Dimas [21]

Answer: it's A

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2 years ago
X + y = -3 &amp; 5x - 2y = -50 ELIMINATION
Karolina [17]
I gotchu luh bro....

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