Question

Can you please for the love of god help me it's 2am and I cannot figure this out​

Answer 1

Answer: a) d(t) = $\frac{13}{14}$ (t - 70) + 65   b: 6:41 pm

duration of time passed:

5:10 pm - 4:00 pm = 70 mins

distance = 65 miles

you points to use to make an equation:

(0,0) and (70,65)  ---------------------> ( (0,0) is bc youre beginning the trip and you have no distance )

find the slope of your "future" equation

$\frac{y_2-y_1}{x_2-x_1}$ = $\frac{65}{70}$ = $\frac{13}{14}$ = m

now use point-slope form

y - 65 =  $\frac{13}{14}$ (x - 70)

y=  $\frac{13}{14}$ (x - 70) + 65

and since it wants it in terms of d and t,

d(t) = $\frac{13}{14}$ (t - 70) + 65

part b:

150 =  $\frac{13}{14}$ (t - 70) + 65

85 = $\frac{13}{14}$ (t - 70)

85 = $\frac{13}{14}$ t - 65

150 = $\frac{13}{14}$ t

2100 = 13t

161.54 = t

about 162 minutes

Thennnn:

162/60 = 2 hours and 41 mins

4:00 pm + 2 hours and 41 mins = 6:41 pm

Answer 2

Answer:

8:05 pm (If you round to the nearest tenth place)

Step-by-step explanation:

basically, 4:00 pm and 5:10 pm have a 1 hour and 10 minute difference.

1 hour and 10 minutes divided by 65 miles is 1.6923076 or 1.7 minutes

1.7 minutes times 150 miles is 2 hours and 55 minuets

2 hours and 55 minutes plus 5:10pm is 8:05 pm

I'm so sorry if I'm wrong!