Answer:
C AND D Y=X-3 IS CONNECTING WITH C AND D AND Y=-2X+1 IS CONNECTING WITH A AND C
Step-by-step explanation:
Answer:
Step-by-step explanation:
I think the quotent is 5, but I recommend waiting for sumone else to answer. Because 31.5 divided by 1.4 equals 22.5 but I'm not sure.
Answer:

Step-by-step explanation:
Given
Electrician = 6
Mechanic = 8
Required
Determine the probability of selecting an electrician
First, we need the total number of employees;



Next, is to determine the required probability using the following formula;


Divide numerator and denominator by 2

<em>Hence, the probability of selecting an electrician is 3/7</em>

Let the capacity of bus be x students
And van be y students, now ;
From the given statements we get two equations ~


multiply the equation (2) with 2 [ it won't change the values ]


Now, deduct equation (1) from equation (3)




Therefore each bus can carry (x) = 45 students
Now, plug the value of x in equation (1) to find y ~







Hence, each van can carry (y) = 17 students in total.