Based in the given figure, we are being asked to solve the area and the perimeter of the semicircle. As we evaluate the problem, we can get a radius measurement from the rectangle. Hence, the radius is half of 4 inches which is 2 inches and since we know the formula for solving the area of a circle which is Area = pi*r², dividing the result by two, we able to get the area of the half of a circle which is equivalent to the area of the semicircle.
Area of circle = pi*r²
Area of circle = 3.14*(2)² = 12.56
Therefore, area of semicircle is = (1/2) 12.56
Area of semicircle = 6.28 inches²
Solving for the perimeter:
Semicircle Perimeter = 1/2 * pi* d+d where d is the diameter (diameter = 4 inches)
Semicircle Perimeter = 1/2 * 3.14*4+4
Semicircle Perimeter = 10.28 inches
Answer:
486 cm
Step-by-step explanation:
9×9=81
there are 6 faces
81×6=486
Answer:
I am not pretty sure
Step-by-step explanation:
You just try it in another way if this is the answer this method is correct
Answer:
Option C. x^2-18x-81
Step-by-step explanation:
A. 16a^2-72a+81
x^2-2xy+y^2=(x-y)^2
x^2=16a^2→sqrt(x^2)=sqrt(16a^2)→x=sqrt(16) sqrt(a^2)→x=4a
y^2=81→sqrt(y^2)=sqrt(81)→y=9
2xy=2(4a)(9)→2xy=72a equal to the second term of the expression, then we can factor as a perfect square trinomial:
16a^2-72a+81=(4a-9)^2
B. 169x^2+26xy+y^2
a^2+2ab+b^2=(a+b)^2
a^2=169x^2→sqrt(a^2)=sqrt(169x^2)→a=sqrt(169) sqrt(x^2)→a=13x
b^2=y^2→sqrt(b^2)=sqrt(y^2)→b=y
2ab=2(13x)(y)→2ab=26xy equal to the second term of the expression, then we can factor as a perfect square trinomial:
169x^2+26xy+y^2=(13x+y)^2
C. x^2-18x-81
a^2+2ab+b^2=(a+b)^2
This expression does not factor as a perfect square trinomial because the third term is negative (-81).
D. 4x^2+4x+1
a^2+2ab+b^2=(a+b)^2
a^2=4x^2→sqrt(a^2)=sqrt(4x^2)→a=sqrt(4) sqrt(x^2)→a=2x
b^2=1→sqrt(b^2)=sqrt(1)→b=1
2ab=2(2x)(1)→2ab=4x equal to the second term of the expression, then we can factor as a perfect square trinomial:
4x^2+4x+1=(2x+1)^2
Subtract 23 and 11 and you’ll get the answer
