Your question could be stated better but the answer is 56, just devide 900/16.
Answer:
Step-by-step explanation:
(x₁ , y₁) = (-4, 1) & (x₂ , y₂) =(-2 , -5)
![Slope =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\\\=\dfrac{-5-1}{-2-[-4]}\\\\\\= \dfrac{-6}{-2+4}\\\\\\= \dfrac{-6}{2}\\\\\\= - 3](https://tex.z-dn.net/?f=Slope%20%3D%5Cdfrac%7By_%7B2%7D-y_%7B1%7D%7D%7Bx_%7B2%7D-x_%7B1%7D%7D%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%7B-5-1%7D%7B-2-%5B-4%5D%7D%5C%5C%5C%5C%5C%5C%3D%20%5Cdfrac%7B-6%7D%7B-2%2B4%7D%5C%5C%5C%5C%5C%5C%3D%20%5Cdfrac%7B-6%7D%7B2%7D%5C%5C%5C%5C%5C%5C%3D%20-%203)
Answer:
b) Yes, the triangles are similar by the SSS similarity
√72 = √4 * √18 = 2√18. Therefore her answer is incorrect.
√72 = √4 * √9 * √2 = 6√2.
Since √2 is approximately 1.41,
6 * 1.41 = 8.46 = 8.5 (nearest tenth).
Answer:
a)
: t=13 seconds
: t<13 seconds
b) At α= 0.01, one-tailed critical value is -2.33
c) Test statistic is −2,98
d) since -2.98<-2.33, we can reject the null hypothesis. There is significant evidence that mean pit stop time for the pit crew is less than 13 seconds at α= 0.01.
Step-by-step explanation:
according to the web search, the question is missing some words, one part should be like this:
"A pit crew claims that its mean pit stop time ( for 4 new tires and fuel) is less than 13 seconds."
Let t be the mean pit stop time of the pit crew.
: t=13 seconds
: t<13 seconds
At α= 0.01, one-tailed critical value is -2.33
Test statistic can be calculated using the equation:
where
- X is the sample mean pit stop time (12.9 sec)
- M is the mean pit stop time assumed under null hypothesis (13 sec)
- s is the population standard deviation (0.19 sec.)
- N is the sample size (32)
Then
≈ −2,98
since -2.98<-2.33, we can reject the null hypothesis. There is significant evidence that mean pit stop time for the pit crew is less than 13 seconds at α= 0.01.